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Zolol [24]
3 years ago
13

I'll show a pic of my question​

Mathematics
1 answer:
Hunter-Best [27]3 years ago
7 0

Answer:

Umm I think you forgot to send the pic with this question  

Step-by-step explanation:

Hope I can help next time!!!!!!

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The television station has received/A many complaints about/B
NARA [144]

<u>The television station has received/A many complaints about/B the clothing advertisements, which some/C viewers condemn to be/D </u><u>tasteless</u><u>. No error/E</u>

The correct option is D.

  • The television station has received many complaints about the clothing advertisements, which some viewers complained were tasteless.
  • Well, you could mean that  Writing Question is a 'trick one' .

What is a television station called?

  • Most often the term "television station" refers to a station which broadcasts structured content to an audience or it refers to the organization that operates the station.
  • A terrestrial television transmission can occur via analog television signals or, more recently, via digital television signals.

Learn more about television station

brainly.com/question/2851169

#SPJ4

6 0
2 years ago
How to prove this???
swat32
\cos^3 2A + 3 \cos 2A \\&#10;\Rightarrow \cos 2A (\cos^2 2A + 3) \\&#10;\Rightarrow (\cos^2 A - \sin^2 A) (\cos^2 2A + 3)  \\&#10;\Rightarrow (\cos^2 A - \sin^2 A) (1 - \sin^2 2A + 3) \\&#10;\Rightarrow (\cos^2 A - \sin^2 A) (4 - \sin^2 2A) \\&#10;\Rightarrow (\cos^2 A - \sin^2 A) (4 - (2\sin A \cos A)(2\sin A \cos A)) \\&#10;\Rightarrow (\cos^2 A - \sin^2 A) (4 - 4\sin^2 A \cos^2 A) \\ &#10;\Rightarrow 4(\cos^2 A - \sin^2 A) (1 - \sin^2 A \cos^2 A) &#10;

go to right side now

4( \cos^6 A - \sin^6 A)\\&#10;\Rightarrow 4( \cos^3 A - \sin^3 A)(\cos^3 A + \sin^3 A)

use x^3 - y^3 = (x-y)(x^2 + xy + y^2) and x^3 + y^3 = x^2 - xy + y^2

4( \cos^6 A - \sin^6 A)\\ \Rightarrow 4( \cos^3 A - \sin^3 A)(\cos^3 A + \sin^3 A) \\&#10;\Rightarrow  4(\cos A - \sin A)(\cos^2 A + \cos A \sin A + \sin^2 A) \\&#10;~\quad  \quad\cdot ( \cos A + \sin A)(\cos^2 A - \cos A \sin A + \cos^2 A)

so \sin^2 A + \cos^2 A = 1

4( \cos^6 A - \sin^6 A)\\ \Rightarrow 4(\cos A - \sin A)(\cos^2 A + \cos A \sin A + \sin^2 A) \\ ~\quad \quad\cdot ( \cos A + \sin A)(\cos^2 A - \cos A \sin A + \cos^2 A) \\ \Rightarrow 4(\cos^2 A - \sin^2 A)(1 + \cos A \sin A )(1- \cos A \sin A ) \\ \Rightarrow 4(\cos^2 A - \sin^2 A)(1 - \cos^2 A \sin^2 A )\\ \Rightarrow 4(\cos^2 A - \sin^2 A)(1 - \sin^2 A \cos^2 A ) \\&#10; \Rightarrow Left hand side
4 0
3 years ago
What is the answer to this problem?
Sedaia [141]

Answer:

x = 4.

Step-by-step explanation:

These are exterior  alternate angles which are congruent.

So 21x + 6 = 90

21x = 84

x = 4.

8 0
3 years ago
Given: 2x + 30 = -4(5x -2);<br> Prove: x = -1
Lady_Fox [76]
2x + 30 = -20x + 8
2x + 20x = 8 - 30
22x = -22
x = 1
6 0
3 years ago
at Jared's last tennis match, he completed 65% of his first serves. if he attempted 80 first serves last match, how many did he
Artyom0805 [142]
65% of 80...turn percent to decimal..." of " means multiply
0.65(80) = 52...so he completed 52 first serves
7 0
3 years ago
Read 2 more answers
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