Question

PLZZZZ SOMEBODY HELP ASAP!!!

Answer 1

Part A) 2y(x³+6x-2x²-12)

Part B) 2y(x²+6)(x-2)

Explanation:
Part A)  The GCF of the coefficients is 2, as the smallest coefficient is 2 and they are all even.  The only variable that is in all 4 terms is y, so the GCF is 2y.  Factoring this out of the first term leaves us with x³; from the second term leaves us 6x; from the third term leaves us -2x²; and from the last term leaves us -24.

Part B) Once the GCF is factored out, we group the remaining factor in parentheses, the first two terms together and the last two together:
2y[(x³+6x)+(-2x²-12)]

Take the GCF out of each group:
2y[x(x²+6)+-2(x²+6)]

Factor out what both have in common, x²+6:
2y(x²+6)(x-2)