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zzz [600]
3 years ago
9

How much heat (in kj) is released when 3.600 mol naoh(s) is dissolved in water? (the molar heat of solution of naoh is â445.1 kj

/mol.)?
Chemistry
2 answers:
Fantom [35]3 years ago
8 0
<span>-1602 kj

Sauce:me

Your welcome
</span>
pav-90 [236]3 years ago
6 0

Answer : The amount of heat released is, -1602.36 KJ

Explanation : Given,

Moles of NaOH = 3.600 mole

Molar heat of solution of NaOH = -445.1 KJ/mole

Now we have to calculate the amount of heat released.

As, 1 mole of NaOH is dissolved in water then heat released = - 445.1 KJ

So, 3.600 mole of NaOH is dissolved in water then heat released = -445.1\times 3.600=-1602.36KJ

Therefore, the amount of heat released is, -1602.36 KJ

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Match the following associations. Exothermic or endothermic
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<u>Answer:</u>

<em>1) ∆H is positive \Rightarrow Endothermic </em>

<em>2) E_p>E_r \Rightarrow Endothermic  </em>

<em>3) Energy is absorbed \Rightarrow Endothermic </em>

<em>4) E_r>E_p \Rightarrow Exothermic </em>

<em>5) ∆H is negtive \Rightarrow Exothermic </em>

<em></em>

<u>Explanation:</u>

∆H is called as enthalpy change  

It is also called as Heat of reaction

Energy is required for the bond to break a bond.

Energy is released when a bond is formed.

H_2+Cl_2>2HCl

that is

H-H+Cl-Cl>2H-Cl

We see in this equation, bonds between hydrogen and chlorine molecules gets broken and on the right side bond is formed in HCl.

If energy of products greater than energy of reactants then the reaction enthalpy change is endothermic .

If energy of products lesser than energy of reactants then the reaction enthalpy change is exothermic .

For example  

\Delta H=E_p-E_r

=30KJ-20KJ

=+10KJ

(positive hence endothermic)

\Delta H=E_p-E_r

=10KJ-40KJ

=-30KJ

(negative hence exothermic)

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How many moles of brcl form when 2.74 mol cl2 react with excess br2?
egoroff_w [7]
Following reaction arise between Br2 and Cl2

Br2   +               Cl2     →     2BrCl
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From above balanced reaction, it can be seen that 1 mole of Br2 reacts with 1 mole of Cl2 to form 2 mole of BrCl

Thus, when <span>2.74 mol Cl2 reacts with excess Br2, 2.74 X 2 = 5.48 moles of BrCl will be formed. </span>
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