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Lapatulllka [165]
2 years ago
11

Which of the following can be represented by a single chemical symbol?

Chemistry
1 answer:
alisha [4.7K]2 years ago
3 0

Answer:

Sodium

Explanation:

Sodium is a pure chemical, hence it can be represented by the single chemical symbol Na.

Water has a chemical symbol of H2O, consisting of two, and not one, symbols, H and O.

Sulfate ion consists of a sulfide ion and four oxygen ions (SO4)2-. Hence, it does not fit.

Finally, potassium chloride has a chemical symbol of KCl. Consisting of two different chemical symbols, (K and Cl), it does not fit either.

Hope this helped!

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lorasvet [3.4K]
C.


Because the spinal cord functions primarily in the transmission of neural signals between the brain and the rest of the body
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3 years ago
Mole conversions.<br> Find the number of moles of argon in 607g of argon?
bogdanovich [222]

Answer:

24249.65 mol

Explanation:

n=MM × m

n= 39.95 ×607

n=24249.65

5 0
3 years ago
#PLATOFAM
Vsevolod [243]
Ketones and aldehydes are simple compounds that contain a carbonyl group (a carbon-oxygen double bond). They are considered "simple" because they do not have reactive groups like −OH or −Cl attached directly to the carbon atom in the carbonyl group, as in carboxylic acids containing −COOH<span>.

So your answer would be D.).

I hope that this helps. :)</span>
4 0
3 years ago
Read 2 more answers
Why neutron doesn't contain any charge?​
zhuklara [117]

Answer:

Neutron does not contain any charge because the charge of the quarks that made up the neutron balances each other out.

Hope it helps.

7 0
1 year ago
Read 2 more answers
How much of 45 grams of pu 234 remains after 27 hours if it’s half life is 4.98 hours
nadya68 [22]

Answer:

1.07 g

Explanation:

Half-life of Pu-234 = 4.98 hours

Initially present = 45 g

mass remains after 27 hours = ?

Solution:

Formula

         mass remains = 1/ 2ⁿ (original mass) ……… (1)

Where “n” is the number of half lives

To find "n" for 27 hours

                          n = time passed / half-life . . . . . . . .(2)

put values in equation 2

                          n = 27 hr / 4.98 hr

                          n = 5.4

Mass after 27 hr

Put values in equation 1

          mass remains = 1/ 2ⁿ (original mass)

          mass remains = 1/ 2^5.4 (45 g)

          mass remains = 1/ 42.2 (45 g)

          mass remains =  0.0237 x 45 g

          mass remains =  1.07 g

6 0
3 years ago
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