The concentration of diluted solution is 0.16 M
<u>Explanation:</u>
As, the number of moles of diluted solution and concentrated solution will be same.
So, the equation used to calculate concentration will be:

where,
are the molarity and volume of the concentrated HCl solution
are the molarity and volume of diluted HCl solution
We are given:

Putting values in above equation, we get:

Hence, the concentration of diluted solution is 0.16 M
Answer:
the type is single replacement
Answer:
<em>The parent isotope in the given elements is Radium 226.
</em>
Explanation:
The two elements given in the question are radioactive elements radon and Helium which are formed after an Alpha decay happens in the radium 226 to form Radon 222.
Radon has many isotopes out of which here radon 222 is formed which is a noble gas that is odourless colourless but Radioactive. Again in this reaction helium is formed which is again a noble gas and very light in weight.
Answer:
39.72 g
Explanation:
Given data:
Mass of CsF = 15.2 g
Mass of XeF₆ = 260 g
Mass of Cs[XeF₇] = ?
Solution:
Chemical reaction:
CsF + XeF₆ → Cs[XeF₇]
Number of moles of CsF:
Number of moles = mass/ molar mass
Number of moles = 15.2 g/151.9 g/mol
Number of moles = 0.1 mol
Number of moles of XeF₆ :
Number of moles = mass/ molar mass
Number of moles = 260 g/245.28 g/mol
Number of moles = 1.06 mol
Now we will compare the moles of Cs[XeF₇] with both reactants.
CsF : Cs[XeF₇]
1 : 1
0.1 : 0.1
XeF₆ : Cs[XeF₇]
1 : 1
1.06 ; 1.06
Number of moles of Cs[XeF₇] produce by CsF are less so it will limiting reactant and limit the yield of Cs[XeF₇].
Mass of Cs[XeF₇]:
Mass = number of moles × molar mass
Mass = 0.1 mol × 397.2 g/mol
Mass = 39.72 g