Answer:
Yess their is a difference the ragdoll pose is a genteler variation of the forward fold yoga pose.
Explanation:
In ragdoll pose, you are meant to relax your entire upper body, allowing for a deep release of tension or stress that is stored in your body.
Answer:
The amplitude of the eardrum's oscillation is 6.65×10^-13 m.
Explanation:
Given data:
The sound has a frequency of 262 Hz
The sound level is 84 dB
The air density is 1.21 kg/m^3
The speed of sound is 346 m/s
Solution:
As, Intensity of sound is given by,
I = Io×10^(s/10 db)
I = 2×π^2×ρ×v×f^2×Sm^2
Thus,
Sm = √(Io×10^(s/10 db)) / √( 2×π^2×ρ×v×f^2)
Now, put the values,
Sm = √( 10^-12 × 10^(84/10) ) / √( 2×(3.14)^2×1.21×346×(262)^2 )
Sm = √(2.51×10^-4 / 5.66×10^8)
Sm = √0.443×10^-12
Sm = 6.65×10^-13 m.
Answer:
The net calorific value of the fuel 1 is 40000 kilojoules per kilogram.
The net calorific value of the fuel 2 is 50000 kilojoules per kilogram.
Explanation:
The net calorific value is equal to the heat produced (
), in kilojoules, divided by the mass of the burnt fuel (
). We proceed to calculate the net calorific value of each fuel:
Fuel 1 (
, 
)
The net calorific value of the fuel 1 is 40000 kilojoules per kilogram.
Fuel 2 (
, 
)
The net calorific value of the fuel 2 is 50000 kilojoules per kilogram.
Frequency and wavelength are two variables which are
indirectly proportional.
They are related in the following equation:
f = c / w
Where,
<span>f = frequency c =
speed of light w = wavelength</span>
Since c is constant, we can equate condition 1 and
condition 2:
f1 w1 = f2 w2
When w2 = 3 w1, then f2 becomes:
261.63 w1 = f2 (3 w1)
Cancelling w1:
f2 = 261.63 / 3
<span>f2 = 87.21 Hz</span>
