Answer:
(a) 62.5 m
(b) 7.14 s
Explanation:
initial speed, u = 35 m/s
g = 9.8 m/s^2
(a) Let the rocket raises upto height h and at maximum height the speed is zero.
Use third equation of motion
h = 62.5 m
Thus, the rocket goes upto a height of 62.5 m.
(b) Let the rocket takes time t to reach to maximum height.
By use of first equation of motion
v = u + at
0 = 35 - 9.8 t
t = 3.57 s
The total time spent by the rocket in air = 2 t = 2 x 3.57 = 7.14 second.
Answer:
In my opinion I think that the answer is C sorry If I get this wrong.
Answer:
Pretty sure its -4.8%
Explanation:
Others asked this question and got this as an answer.
Answer:
The answer to your question is letter B.
Explanation:
To answer this question, we must remember the third law of motion of Newton that states that For every action, there is an equal and opposite reaction.
Then, if the action force is 40 N to the right, the reaction force must be 40 N to the left.
Answer:
ummmmmmmmmmmm ask your teacher or perant for help
Explanation:
so umm ask an adult or teen figure and maybe you will get it write not sure do
