Ask question

Ask question

All categories

sleet_krkn [62]

3 years ago

11

A stationary car with a mass of 1500 kg reaches a velocity of 15 meters per second, 5 seconds after starting. What is the car's

acceleration?

1 answer:

Artyom0805 [142]3 years ago

4 0

Answer:

Let me know if you have questions

You might be interested in

Lora (of mass 54 kg) is an expert skier. She

omeli [17]

The mechanical energy at top =Mechanical energy at bottom

Mass=m=54kg
Height=h=51m
Acceleration due to gravity=g=10m/s^2
Velocity=v=2.6m/s

$\\ \tt\longmapsto M_{initial}=M_{Final}$

Final energy at bottom=The kinetic energy

$\\ \tt\longmapsto KE=M_{initial}$

$\\ \tt\longmapsto KE=P.E_{(Top)}+K.E_{(Top)}$

$\\ \tt\longmapsto K.E=mgh+\dfrac{1}{2}mv^2$

$\\ \tt\longmapsto K.E=m\left(gh+\dfrac{v^2}{2}\right)$

$\\ \tt\longmapsto K.E=54\left((10)(51)+\dfrac{2.6^2}{2}\right)$

$\\ \tt\longmapsto K.E=54\left(510+\dfrac{6.76}{2}\right)$

$\\ \tt\longmapsto K .E=54(510+3.38)$

$\\ \tt\longmapsto K.E=54(513.38)$

$\\ \tt\longmapsto K.E=27722.52J$

$\\ \tt\longmapsto K.E=27.7KJ$

6 0

2 years ago

Father drove 176 km in 7 hours. For the first 92 km, he spent

Verizon [17]

Answer:

28km/h

Explanation:

92km = 4 hours

176 - 92 = 84

84km = 3 hours

84/3 = 28

28km/h

Hopefully this helps you :)

pls mark brainlest ;)

3 0

2 years ago

A block of mass 4 kilograms is initially moving at 5m/s on a horizontal surface. There is friction between the block and the sur

Dmitriy789 [7]

Answer:

d = 2.54 [m]

Explanation:

Through the theorem of work and energy conservation, we can find the work that is done. Considering that the energy in the initial state is only kinetic energy, while the energy in the final state is also kinetic, however, this is zero since the body stops.

$E_{k1}+W=E_{k2}\\$

where:

W = work [J]

Ek1 = kinetic energy at initial state [J]

Ek2 = kinetic energy at the final state = 0.

We must remember that kinetic energy can be calculated by means of the following expression.

$\frac{1}{2} *m*v^{2}-W=0\\W= \frac{1}{2} *4*(5)^{2}\\W= 50 [J]$

We know that work is defined as the product of force by distance.

$W=F*d$

where:

F = force [N]

d = distance [m]

But the friction force is equal to the product of the normal force (body weight) by the coefficient of friction.

$f=m*g*0.5\\f = 4*9.81*0.5\\f = 19.62 [N]$

Now solving the equation for the work.

$d=W/F\\d = 50/19.62\\d = 2.54[m]$

4 0

2 years ago

Which elements are metalloids

zhannawk [14.2K]

The six commonly recognised metalloids are boron, silicon, germanium, arsenic, antimony, and tellurium....

7 0

3 years ago

Buffalo, New York, and Raleigh, NC, lie approximately on the same meridian. Buffalo has a latitude of 42.9° N, and Raleigh has a

yulyashka [42]

Answer:

Distance will be $=3960\times 0.12385=490.468miles$

Explanation:

We have given that Buffalo has a latitude of 42.9°N

And Raleigh has a latitude of 35.8°N

Radius of the earth = 3960 miles

We have to calculate the distance between given two cities

Difference in their latitudes = $42.9-35.8=7.1^{\circ}$

Now changing the angle in radian = $7.1\times\frac{\pi }{180}=0.12385radian$

So distance will be $=3960\times 0.12385=490.468miles$

5 0

2 years ago