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lozanna [386]
2 years ago
5

The reaction 4al (s) 3o2 (

Chemistry
2 answers:
irina [24]2 years ago
8 0
The reaction 4al (s) 3o2 (
g. → 2al2o3 (s) δh° = -3351 kj is exothermic________, and therefore heat is _____release ___ by the reaction.
Hunter-Best [27]2 years ago
6 0

<u>Answer:</u> The reaction is exothermic and therefore the heat is released by the reaction.

<u>Explanation:</u>

There are 2 types of reaction based on the heat of the reaction:

  • Exothermic reactions are defined as the reactions in which energy is released in the form of heat. The enthalpy change (\Delta H^o) of the reaction comes out to be negative for this kind of reaction.
  • Endothermic reactions are defined as the reactions in which energy is absorbed in the form of heat. The enthalpy change (\Delta H^o) of the reaction comes out to be positive for this kind of reaction.

For the given chemical reaction:

4Al(s)+3O_2(g)\rightarrow 2Al_2O_3(s);\Delta H^o=-3351kJ

As, the enthalpy change of the reaction is negative. The reaction is considered as an exothermic reaction.

Hence, the reaction is exothermic and therefore the heat is released by the reaction.

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8 0
2 years ago
The reaction of 2-chloropropane with sodium hydroxide can occur via both SN1 and SN2 mechanisms.
strojnjashka [21]

Answer:

Explanation:

(a) Part 1: S_N1 reaction. This is a nucleophilic substitution reaction in which we have two steps. Firstly, chlorine, a good leaving group, leaves the carbon skeleton to form a relatively stable secondary carbocation. This carbocation is then attacked by the hydroxide anion, our nucleophile, to form the final product.

To summarize, this mechanism takes places in two separate steps. The mechanism is attached below.

Part 2: S_N2 reaction. This is a nucleophilic substitution reaction in which we have one step. Our nucleophile, hydroxide, attacks the carbon and then chlorine leaves simultaneously without an intermediate carbocation being formed.

The mechanism is attached as well.

(b) The rate determining step is the slow step. Formation of the carbocation has the greatest activation energy, so this is our rate determining step for S_N1. For S_N2, we only have one step, so the rate determining step is the attack of the nucleophile and the loss of the leaving group.

3 0
3 years ago
ASAP PLLEEASE HURYYYYYYYYYYRRRRRRRRRRRRYY (NO FILES FOR ME NEEDING TO DOWNLAOD PLEASE!)
pickupchik [31]

Answer:

1.Fill in the blank with the correct term to make the statement true.

During the (night)

at the beach, the land cools down

(slower)

than the

(ocean).

Because of this, the air over the land is

(Warmer) than the air over the ocean. The

(More)

dense air rises over the ocean and the cooler,

(More)

dense air blows in from over the land creating a

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breeze.

2.Which statement is true about winds?

Winds always blow from low to high pressure.

true

Winds always blow from water to land.

false

Winds always blow from land to water.

false

3. Winds always blow from high to low pressure. How do landmasses impact the movement of air and water?

They stop all movement of both air and water.

They speed up the air and water and allow it to pass though.

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They slow down the air but speed up the water.

pt:2

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Explanation:

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3 0
3 years ago
Read 2 more answers
Definition of metallurgy
iragen [17]
<span>Definition of Metallurgy-The branch of science and technology concerned with the properties of metals and their production and purification.</span>
8 0
3 years ago
Read 2 more answers
Consider the molecules: scl2, f2, cs2, cf4, and brcl. select the choice where the bonds of the molecules are arranged in order o
elena-s [515]

The polarity of a bond depends on the difference in electronegativities of the atoms involved in bonding. Greater this difference, greater is the polarity

1) In SCl2 we have the S-Cl bond

Electronegativity values: S = 2.5, Cl = 3

Difference = 3.0 -2.5 = 0.5

2) In F2 we have the F-F bond

Electronegativity value: F = 4.0

Difference = 4.0-4.0 = 0

3) In CS2 we have the C-S bond

Electronegativity value: C = 2.5, S = 2.5

Difference = 2.5 -2.5 = 0

4) In CF4 we have the C-F bond

Electronegativity values: C = 2.5, F = 4.0

Difference = 4.0 -2.5 = 1.5

5) In BrCl we have the Br-Cl bond

Electronegativity values: Br = 2.8, Cl = 3

Difference = 3.0 -2.8 = 0.2

Therefore, the increasing order of polarity is

F2 = CS2 < BrCl < SCl2 < CF4

5 0
3 years ago
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