13/6-9/7
Find the Least Common Denominator (LCD)
In this case, 42.
(7/7)(13/6)-(6/6)(9/7)
37/42 is your answer
Question:
Morgan is playing a board game that requires three standard dice to be thrown at one time. Each die has six sides, with one of the numbers 1 through 6 on each side. She has one throw of the dice left, and she needs a 17 to win the game. What is the probability that Morgan wins the game (order matters)?
Answer:
1/72
Step-by-step explanation:
<em>Morgan can roll a 17 in 3 different ways. The first way is if the first die comes up 5, the second die comes up 6, and the third die comes up 6. The second way is if the first die comes up 6, the second die comes up 5, and the third die comes up 6. The third way is if the first die comes up 6, the second die comes up 6, and the third die comes up 5. For each way, the probability of it occurring is 1/6 x 1/6 x 1/6 = 1/216. Therefore, since there are 3 different ways to roll a 17, the probability that Morgan rolls a 17 and wins the game is 1/216 + 1/216 + 1/216 = 3/216 = 1/72</em>
<em>I had this same question on my test!</em>
<em>Hope this helped! Good Luck! ~LILZ</em>
What you’ll have to do is find the probability of the oranges and the tangerines. There is a total is 15 fruit. 12 of those are not grapefruit. You’ll then have to find the percentage of 12/15.
12 is divided by 15, then multiplied by 100.
12 divided by 15 = 0.08
0.08 x 100 = 80
There is an 80% chance that a grapefruit will not be picked.
√4 / 9
√4 = 2
So the answer would be....
2 / 9
Hope this helps!
