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Olin [163]
3 years ago
12

On a True/False test, Amy answered the first three questions wrong but answered the rest of the questions correctly. On the same

test, Scott answered exactly two questions wrong. He answered the last question wrong, the 26 questions before it correctly, and the question before that wrong. If Amy and Scott were both incorrect on the same question exactly once, what is the greatest possible percent of the total number of questions that Amy could have answered correctly?
Mathematics
1 answer:
borishaifa [10]3 years ago
3 0

Answer:

89.29%

Step-by-step explanation:

Given that Scott answered exactly two questions wrong. He answered the last question wrong, the 26 questions before it correctly, and the question before that wrong.  Since Amy and Scott were both incorrect on the same question exactly once, Scott would have done wrong only in I or II or III question.  If I question was wrong by both, total questions = 28, if II wrong total questions =29 and for iii total questions =30

Greatest possible percent would occur if total questions are less

i.e. when total =28

Greatest percent = \frac{28-3}{28} =89.29%

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Answer:

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Step-by-step explanation:

We are given that Karri takes a 7 question true-false test and guess on every question.

The above situation can be represented through binomial distribution;

P(X = r) = \binom{n}{r} \times p^{r} \times (1-p)^{n-r} ; x = 0,1,2,3,........        

where, n = number of samples (trials) taken = 7 question

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            p = probability of success which in our question is probability that

                   question is correct, i.e. p = 50%

Let X = <u><em>Number of question that are correct</em></u>

So, X ~ Binom(n = 7, p = 0.50)

Now, the  probability that she gets all 7 questions correct is given by = P(X = 7)

         P(X = 7)  =  \binom{7}{7} \times 0.50^{7} \times (1-0.50)^{7-7}

                        =  1 \times 0.50^{7} \times 0.50^{0}

                        =  <u>0.0078</u>

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Aleksandr-060686 [28]

9514 1404 393

Answer:

  A.  ∠EAG and ∠BAC

Step-by-step explanation:

Vertical angles share a vertex and have opposite rays for sides.

Rays AE and AB are opposite; rays AG and AC are opposite. These are the only pairs of opposite rays in the figure, so the vertical angles must be constructed from one of the rays of the first pair and one of the rays of the second pair. ∠EAG and ∠BAC are a pair of vertical angles.

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Answer:

5

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→ Let x = √20 + √20 .....

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