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Olin [163]
3 years ago
12

On a True/False test, Amy answered the first three questions wrong but answered the rest of the questions correctly. On the same

test, Scott answered exactly two questions wrong. He answered the last question wrong, the 26 questions before it correctly, and the question before that wrong. If Amy and Scott were both incorrect on the same question exactly once, what is the greatest possible percent of the total number of questions that Amy could have answered correctly?
Mathematics
1 answer:
borishaifa [10]3 years ago
3 0

Answer:

89.29%

Step-by-step explanation:

Given that Scott answered exactly two questions wrong. He answered the last question wrong, the 26 questions before it correctly, and the question before that wrong.  Since Amy and Scott were both incorrect on the same question exactly once, Scott would have done wrong only in I or II or III question.  If I question was wrong by both, total questions = 28, if II wrong total questions =29 and for iii total questions =30

Greatest possible percent would occur if total questions are less

i.e. when total =28

Greatest percent = \frac{28-3}{28} =89.29%

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Zinaida [17]
6 = 2(x+8) - 5x
⇒ 2x+ 2*8 -5x= 6
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geniusboy [140]

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Answer:

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Step-by-step explanation:

Since our equation is F=\frac{Gm_1m_2}{r^2} and we want to solve for G, first we divide both sides by the product m_1m_2, which gives:

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So we are left with:

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Now we multiply both sides by r^2, which gives:

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2 years ago
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Kobotan [32]

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6 0
3 years ago
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