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artcher [175]
3 years ago
11

Calculate the number of moles in the 2.1-L volume of air in the lungs of the average person. Note that the air is at 37.0ºC (bod

y temperature). Use standard atmospheric pressure.
Chemistry
1 answer:
adelina 88 [10]3 years ago
7 0
Answer: 0.0826mol

PV=nRT
n=PV/RT
n=(1atm)(2.1L)/(310K)(0.082057L*atm/mol*K)=0.0826mol
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The molarity of aqueous lithium bromide, LiBr solution is 0.2 M

We'll begin by calculating the number of mole of Pb(NO₃)₂ in the solution.

  • Volume = 10 mL = 10 / 1000 = 0.01 L
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Mole = Molarity x Volume

Mole of Pb(NO₃)₂ = 0.25 × 0.01

Mole of Pb(NO₃)₂ = 0.0025 mole

Next, we shall determine the mole of LiBr required to react with 0.0025 mole of Pb(NO₃)₂

Pb(NO₃)₂ + 2LiBr —> PbBr₂ + 2LiNO₃

From the balanced equation above,

1 mole of Pb(NO₃)₂ reacted with 2 mole of LiBr.

Therefore,

0.0025 mole of Pb(NO₃)₂ will react with = 2 × 0.0025 = 0.005 mole of LiBr

Finally, we shall determine the molarity of the LiBr solution

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Molarity = mole / Volume

Molarity of LiBr = 0.005 / 0.025

Molarity of LiBr = 0.2 M

Learn more about molarity: brainly.com/question/10103895

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The answer is C.

You're welcome!

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Explanation:

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Answer: X: High and Y: High

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