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artcher [175]
3 years ago
11

Calculate the number of moles in the 2.1-L volume of air in the lungs of the average person. Note that the air is at 37.0ºC (bod

y temperature). Use standard atmospheric pressure.
Chemistry
1 answer:
adelina 88 [10]3 years ago
7 0
Answer: 0.0826mol

PV=nRT
n=PV/RT
n=(1atm)(2.1L)/(310K)(0.082057L*atm/mol*K)=0.0826mol
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What are the empirical formula and empirical formula mass for C10H30O10?
AysviL [449]

Answer:

Empirical formula: CH₃O

Empirical formula mass = 31 g/mol

Explanation:

Data Given:

Molecular Formula = C₁₀H₃₀O₁₀

Empirical Formula = ?

Empirical Formula mass =

Solution

Empirical Formula:

Empirical formula is the simplest ration of atoms in the molecule but not all numbers of atoms in a compound.

So,

The ratio of the molecular formula should be divided by whole number to get the simplest ratio of molecule

As

C₁₀H₃₀O₁₀ Consist of  10 Carbon (C) atoms, 30 Hydrogen (H) atoms, and 10 Oxygen (O) atoms.

Now

Look at the ratio of these three atoms in the compound

                         C : H : O

                        10 : 30 : 10

Divide the ratio by two to get simplest ratio

                          C      :   H      :    O

                         10/10 : 30/10 : 10/10

                             1 : 3 : 1

So for the empirical formula the simplest ratio of carbon to hydrogen to oxygen is 1:3:1

So the empirical formula will be

                     Empirical formula of C₁₀H₃₀O₁₀ =  CH₃O

Now

To find the empirical formula mass in g/mol

Formula mass:

Formula mass is the total sum of the atomic masses of all the atoms present in a formula unit.

**Note:

if we represent the molar mass of the empirical formula for one mol in grams then it is written as g/mol

So,

As the empirical formula of C₁₀H₃₀O₁₀ is CH₃O

Then Its empirical formula mass will be

CH₃O

Atomic Mass of C = 12

Atomic Mass of H = 3

Atomic Mass of O = 16

Total Molar mass of CH₃O

CH₃O = 12 + 3(1) + 16

CH₃O = 12 + 3 + 16

CH₃O = 31 g/mol

4 0
2 years ago
Crude oil pumped out of the ground may be accompanied by formation water, a solution that contains high concentrations of nacl a
djverab [1.8K]

solution:

the change in the boiling point is given as,

dTbp =2.30°c

elevation constant for the solvent is given by,

kb=0.512°c/m

molality=\frac{dTBP}{KB\times m}\\=\frac{2.30}{0.512c/m}

= 4.49m

8 0
3 years ago
Is the mold on bread made up of cells​
Harman [31]

Answer:

Yes.

Explanation:

Mold is a living organism. All living organisms are made up of cells.

5 0
3 years ago
Study the solutions in the glasses. Put the solutions in order from concentrated to dilute.
Svetach [21]
A. 1,2,3. The solutions are getting lighter meaning the concentration is decreasing. Its most likely that water was added to dilute the solutions.
8 0
3 years ago
Which element has properties most similar to Bromine? <br> A) F <br> B) Kr <br> C) S <br> D) Se
Stells [14]
Fluorine (F) will have properties similar to Bromine (Br) because it belongs to the same group as Bromine.
7 0
3 years ago
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