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Bumek [7]
3 years ago
12

A hot metal plate at 150°C has been placed in air at room temperature. Which event would most likely take place over the next fe

w minutes?
Molecules in both the metal and the surrounding air will start moving at lower speeds.
Molecules in both the metal and the surrounding air will start moving at higher speeds.
The air molecules that are surrounding the metal will slow down, and the molecules in the metal will speed up.
The air molecules that are surrounding the metal will speed up, and the molecules in the metal will slow down.
Chemistry
1 answer:
zubka84 [21]3 years ago
8 0

Answer:

The air molecules that are surrounding the metal will speed up, and the molecules in the metal will slow down.

Explanation:

There will be a transfer of thermal energy (heat) from the hot metal plate to the surrounding air. This transfer of energy equates to a transfer of kinetic energy in the molecules. As the plate loses heat, the molecules in the plate will lose kinetic energy and slow down. As the surrounding air gains heat, the molecules will gain kinetic energy and speed up.

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if .709 j of heat is added to water and cause the temperature to go up by .036 degrees C what mass of water is present
liberstina [14]

Answer:

0.00471 grams H₂O

Explanation:

To determine the mass, you need to use the following equation:

Q = mcΔT

In this equation,

-----> Q = energy/heat (J)

-----> m = mass (g)

-----> c = specific heat capacity (J/g°C)

-----> ΔT = temperature change (°C)

The specific heat capacity of water is 4182 J/g°C. You can plug the given values into the equation and simplify to isolate "c".

Q = 0.709 J                            c = 4182 J/g°C

m = ? g                                   ΔT = 0.036 °C

Q = mcΔT                                                    <----- Equation

0.709 J = m(4182 J/g°C)(0.036 °C)            <----- Insert values

0.709 J = m(150.552)                                 <----- Multiply 4182 and 0.036

0.00471 = m                                              <----- Divide both sides by 150.552

8 0
1 year ago
What did J. J. Thomson observe when he applied electric voltage to a cathode ray tube in his famous experiment?
Nataly_w [17]

The glass opposite to the negative electrode started to glow. Hence, option B is correct.

<h3>What is a cathode ray tube?</h3>

A cathode-ray tube (CRT) is a specialized vacuum tube in which images are produced when an electron beam strikes a phosphorescent surface.

J.J. Thomson, through his famous Cathode ray experiment, proved that all atoms contain small negatively charged particles known as electrons. In the experiment, he applied electric voltage across a cathode ray tube. a fluorescent material coating was done on the positive side. When the voltage was applied, the positive side has glowing dots.

Hence, option B is correct.

Learn more about the cathode ray tube here:

brainly.com/question/14409449

#SPJ1

6 0
2 years ago
1. Name three obstacles that Mendeleev faced in his life? ​
Fittoniya [83]

Answer:

was difficult to place isotopes of elements as they have the same chemical properties but different atomic masses. It was not possible to predict how many elements could be discovered between two heavy elements as the rise in atomic mass is not uniform.

3 0
3 years ago
5 properties of acids
Dahasolnce [82]

Answer:

   Acids change the color of litmus from blue to red.

   They convert the color of Methyl Orange from Orange/Yellow to Pink.

   Acids turn the pink color of Phenolphthalein to colourless.

   Acids can conduct electricity.

   Some Acids are highly corrosive in nature which means that they corrode or rust metals.

Explanation:

hope this helped

ur boi johnny joestar.

8 0
3 years ago
Read 2 more answers
A solute is a strong electrolyte that ionizes into 2 ions. What is the molar mass of this solute if 30.76 grams added to exactly
Whitepunk [10]

Answer:

34.9 g/mol is the molar mass for this solute

Explanation:

Formula for boiling point elevation: ΔT = Kb . m . i

ΔT = Temperatures 's difference between pure solvent and solution → 0.899°C

Kb = Ebullioscopic constant → 0.511°C/m

m = molality (moles of solute/1kg of solvent)

i = 2 → The solute is a strong electrolyte that ionizes into 2 ions

For example: AB ⇒ A⁺  +  B⁻

Let's replace → 0.899°C = 0.511 °C/m . m . 2

0.899°C / 0.511 m/°C . 2 = m → 0.879 molal

This moles corresponds to 1 kg of solvent. Let's determine the molar mass

Molar mass (g/mol) → 30.76 g / 0.879 mol = 34.9 g/mol

4 0
3 years ago
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