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Anton [14]
3 years ago
13

Sex cells are produced during the process of

Chemistry
2 answers:
Svetradugi [14.3K]3 years ago
6 0
<span>Sex cells (also known as gametes)  are produced during the process of meiosis</span>
11Alexandr11 [23.1K]3 years ago
5 0
Mitosis is the process
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B. Determine the percent composition of each element in NaCl. (1 point) Must show work to
andrey2020 [161]

Answer:

Sodium (Na): (.5 point)

22.99+35.453=58.433.   22.99/58.433=   39%

Chlorine (Cl): (.5 point)

22.99+35.453=58.433.   35.453/58.433= 61%

Explanation:

8 0
2 years ago
Why are metals malleable?
Tema [17]

Answer:

b is the anwer

Explanation:

the option is the explanation

4 0
3 years ago
The frequency factors for these two reactions are very close to each other in value. Assuming that they are the same, compute th
MrRissso [65]

The question is incomplete, complete question is :

The frequency factors for these two reactions are very close to each other in value. Assuming that they are the same, compute the ratio of the reaction rate constants for these two reactions at 25°C.

\frac{K_1}{K_2}=?

Activation energy of the reaction 1 ,Ea_1 = 14.0 kJ/mol

Activation energy of the reaction 2,Ea_1  = 11.9 kJ/mol

Answer:

0.4284 is the ratio of the rate constants.

Explanation:

According to the Arrhenius equation,

K=A\times e^{\frac{-Ea}{RT}}

The expression used with catalyst and without catalyst is,

\frac{K_2}{K_1}=\frac{A\times e^{\frac{-Ea_2}{RT}}}{A\times e^{\frac{-Ea_1}{RT}}}

\frac{K_2}{K_1}=e^{\frac{Ea_1-Ea_2}{RT}}

where,

K_2 = rate constant reaction -1

K_1 = rate constant reaction -2

Activation energy of the reaction 1 ,Ea_1 = 14.0 kJ/mol = 14,000 J

Activation energy of the reaction 2,Ea_1  = 11.9 kJ/mol = 11,900 J

R = gas constant = 8.314 J/ mol K

T = temperature = 25^oC=273+25=298 K

Now put all the given values in this formula, we get

\frac{K_1}{K_2}=e^{\frac{11,900- 14,000Jl}{8.314 J/mol K\times 298 K}}=2.3340

0.4284 is the ratio of the rate constants.

7 0
3 years ago
I have no idea what to put, pls help, due tmr<br>(science)​
rodikova [14]

Answer:

It traveled for 4 seconds at a distance of about 4.1 meters. With a velocity of 10%.

Explanation:

6 0
3 years ago
Which of these would be a good topic for a descriptive investigation? A. how the Moon's appearance changes B. what kind of dog f
katen-ka-za [31]

A. how the Moon's appearance changes

Explanation:

Descriptive investigation use very careful observations and measurements to develop findings.

Most geologists, meteorologists and astronomers use descriptive investigation to develop their findings.

  • Since most of their subject matter is inaccessible.
  • Descriptive investigation is used for indirectly making inquiries
  • It involves the development of an inquiry without formulating any hypothesis.

learn more:

Experiments brainly.com/question/1621519

#learnwithBrainly

6 0
3 years ago
Read 2 more answers
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