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elixir [45]
3 years ago
9

As a chemical reaction occurs, the thermometer in the container records an increase in temperature. What is true of the reaction

?
The reaction is endothermic because heat was taken in by the reaction.

The reaction is exothermic because heat was released by the reaction.

The reaction is endothermic because heat was released by the reaction.

The reaction is exothermic because heat was taken in by the reaction.
Chemistry
2 answers:
iren2701 [21]3 years ago
7 0
The second one is correct
Serga [27]3 years ago
5 0

Answer:

The reaction is exothermic because heat was released by the reaction.

Explanation:

'exothermic' means a reaction released heat over the time of the experiment.

'endothermic' means that the reaction released cold over the experiment.

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Given the chemical reaction: Hg2+(aq) + Cu(s) + Hg(s) + Cu2+(aq)
Pavel [41]

Answer: When the reaction reaches equilibrium, the cell potential will be 0.00 V

Explanation:

Equilibrium state is the state when reactants and products are present but the concentrations does not change with time.

The equilibrium is dynamic in nature and the reactions are continuous in nature. Rate of forward reaction is equal to the rate of backward reaction.

The standard emf of a cell is related to Gibbs free energy by following relation:

\Delta G=-nFE^0

The Gibbs free energy is related to equilibrium constant by following relation:

\Delta G=-2.303RTlog K

For equilibrium \Delta G=0

Thus 0=-nFE^0

E^0=0

Thus When the reaction reaches equilibrium, the cell potential will be 0.00 V

5 0
3 years ago
Which of these solutions is the most basic?
dalvyx [7]
<h2>Question↷</h2>

Which of these solutions is the most basic?

[OH-] = 4.3 x 10-9 M

[OH-] = 2.8 x 10-11 M

[OH-] = 6.7 x 10-10 M

[OH-] = 1.0 x 10-5 M

<h2>Answer↷</h2>

  • <u>[OH-] = 1.0 x 10-5 M</u> ✓

<h2>Solution↷</h2>

[OH-] = 4.3 x 10-9 M

  • [OH-] = 4.3 x 10^-9 M
  • pOH = - log [OH^1-]
  • pOH = - log [4.3 x 10^-9]
  • pOH = 8.36
  • pH = 14- 8.36
  • pH = 5.64

_______________________________________

[OH-] = 2.8 x 10-11 M

  • [OH-] = 2.8 x 10^-11 M
  • pOH = - log [OH^1-]
  • pOH = - log [2.8 x 10^-11 ]
  • pOH = 10.55
  • pH = 14-10.55
  • pH = 3.45

_______________________________________

[OH-] = 6.7 x 10-10 M

  • [OH-] = 6.7 x 10^-10 M
  • pOH = - log [OH^1-]
  • pOH = - log [6.7 x 10^-10]
  • pOH = 9.17
  • pH = 14-9.17
  • pH = 4.83

_______________________________________

[OH-] = 1.0 x 10-5 M

  • [OH-] = 1.0 x 10-5 M
  • pOH = - log [OH^1-]
  • pOH = - log [1.0 x 10^-5 ]
  • pOH = 5
  • pH = 14-5
  • pH = 9

_______________________________________

we know that , the solution with <u>pH > 7</u> is termed as basic and more the pH ,more the basicity, hence ,the solution with the highest pH would be the strongest base out of these all which is

<u>[OH-] = 1.0 x 10-5 M</u> with pH = 9

_______________________________________

4 0
2 years ago
Read 2 more answers
How many atoms exist in 100.0 grams of lithium
Feliz [49]
Mass of Li: 6.94 g Li
Conversion relationship: 1 mole Li=6.94 g Li
100.0 g Li 1 mole Li
---------- x ---------- = 14.4 moles Li
1 6.94 g Li
Conversion relationship: 1 mole Li=6.02x10^23 atoms Li
14.4 moles Li 6.02x10^23 atoms Li
-------------- x ----------------------- = 8.67x10^24 atoms Li
1 1 mole Li
3 0
2 years ago
A student wonders whether a piece of jewelry is made of pure silver. She determines that its mass is 3.25 g. Then she drops it i
Anettt [7]

Answer:

The jewelry is 2896.54_Kg/m^3 less dense than pure silver

Explanation:

Density of jewellery = (mass of jewellery) ÷ (volume of jewellery)

=3.25g ÷ 0.428mL = 0.00325Kg÷0.000000428m^3 = 7583.46Kg/m^3

The density of silver is 10490_Kg/m^3 which is (10490 - 7583.46) 2896.54_Kg/m^3 more dense than the jewellery

The density of Silver [Ag]

The weight of Silver per cubic centimeter is 10.49 grams or the weight of silver per cubic meter is 10490 kilograms, that is the density of silver is 10490 kg/m³; at 20°C (68°F or 293.15K) at a pressure of one atmospheres.

3 0
2 years ago
Set Grouper to 70%. How do you think this level of fishing will affect the populations of the other fish in the simulated reef?
nordsb [41]

Answer:

Greatly affect.

Explanation:

This level of fishing will greatly affect the populations of the other fish in the simulated reef because overfishing disturbs the equilibrium in the marine ecosystem. One fish is a food of another fish or the big fish act as a controller which controls the population of other small fishes and in that way the ecosystem is present in equilibrium state so overfishing will greatly affect the marine ecosystem.

3 0
2 years ago
Read 2 more answers
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