For this case, we can model the problem as a triangle with a right angle.
Where,
x, y: lengths of the sides of the triangle
d: hypotenuse of the triangle
We then have the following relationship:

Clearing d we have:
Answer:
A functions that would best model the situation above is:
D square root
Answer:
Kaitlin's answer is wrong because she is supposed to by dividing. When trying to get rid of a number from a variable you have to divide the number by itself and whatever you do to one side you have to do to the other side
so you would do 5/5 - cancels out
15/5=3
y=3
Step-by-step explanation:
have a great day :D
Answer:
option 4
Step-by-step explanation:
using the equation stated above
1st term = -6+(1-1=0)*(6)=-6
4th term= -6+(4-1=3)*6=12
10th term= -6+(10-1=9)*6=48
Answer:
3) y = 2
Step-by-step explanation:
Step : 1
given 2 y-1 =3
Adding '1 ' on both sides, we get
2 y -1 +1 = 3+1
2 y = 4
dividing by '2' on both sides, we get

cancelling '2' on both sides, we get
y = 2