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Doss [256]
3 years ago
10

The biology class has a lab every 4 days. the earth science class has a lab every 3 days. On which day do both classes have lab

Mathematics
1 answer:
Anon25 [30]3 years ago
5 0
They both have a lab not eh twelfth day because 4,8,12 And then 3,9,12
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A study of the number of business lunches that executives in the insurance and banking industries claim as deductible expenses p
gizmo_the_mogwai [7]

Answer:

t=\frac{9.1-8}{\sqrt{\frac{(1.9)^2}{40}+\frac{(2.1)^2}{50}}}}=2.604  

p_v =2*P(t_{(88)}>2.604)=0.0108

So the p value is a very low value and using any significance level for given \alpha=0.05 always p_v so we can conclude that we have enough evidence to reject the null hypothesis, and there is enough evidence to conclude that the two means are significantly different at 5%

Step-by-step explanation:

Data given and notation

\bar X_{1}=9.1 represent the mean for the sample 1

\bar X_{2}=8 represent the mean for the sample 2

s_{1}=1.9 represent the sample standard deviation for the sample 1

s_{2}=2.1 represent the sample standard deviation for the sample 2

n_{1}=40 sample size for the group 1

n_{2}=50 sample size for the group 2

t would represent the statistic (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to check if the mean are different , the system of hypothesis would be:

Null hypothesis:\mu_{1} = \mu_{2}

Alternative hypothesis:\mu_{1} \neq \mu_{2}

If we analyze the size for the samples both are higher than 30 and the population deviations are not given, so for this case is better apply a t test to compare means, and the statistic is given by:

t=\frac{\bar X_{1}-\bar X_{2}}{\sqrt{\frac{s^2_{1}}{n_{1}}+\frac{s^2_{2}}{n_{2}}}} (1)

t-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.

Calculate the statistic

We can replace in formula (1) the results obtained like this:

t=\frac{9.1-8}{\sqrt{\frac{(1.9)^2}{40}+\frac{(2.1)^2}{50}}}}=2.604  

Statistical decision

The first step is calculate the degrees of freedom, on this case:

df=n_{1}+n_{2}-2=40+50-2=88

Since is a bilateral test the p value would be:

p_v =2*P(t_{(88)}>2.604)=0.0108

So the p value is a very low value and using any significance level for given \alpha=0.05 always p_v so we can conclude that we have enough evidence to reject the null hypothesis, and there is enough evidence to conclude that the two means are significantly different at 5%

3 0
3 years ago
max and his friend zeke are comparing their ages. they figure out that if they double maxs age from 3 years ago and add it to ze
Gre4nikov [31]
Let m be max's age
Let z be zekes age
2m+z=26
Sub in zekes age
2m+8=26
2m=26-8
2m=18
M=18/2
M=9
Remember: this is Max's age THREE YEARS AGO. Therefore, add three to get his current age
9+3=12
Therefore, Max is currently 12
Hope this helps!
4 0
3 years ago
Read 2 more answers
How to solve this problem
finlep [7]

the answer  is 134 and the Remainder is 19

6 0
3 years ago
K is the midpoint of JL. JK = 2x + 5 and JL = 50.
Sergeu [11.5K]
Steve set the equation equal to 50 which is the entire length of JL. instead he should've set the equation equal to 25, since it's half of 50 and would represent the midpoint. he should've said 2x + 5 = 25
8 0
3 years ago
Help Will give brainless<br> What is the slope of the line represented by the values in the table?
Olin [163]

Answer:

Slope = 2

Step-by-step explanation:

Slope = 20/10 = 2

6 0
3 years ago
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