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frozen [14]
3 years ago
8

A shorter electromagnetic wave is _____. more powerful less powerful hotter colder

Physics
2 answers:
Svet_ta [14]3 years ago
8 0
<u>Answer</u>

more powerful 

<u>Explanation</u>
Electromagnetic waves are waves that do not require material medium for propagation. For example x-rays, UV and gamma rays.

From the wave equation, V= λf, when the wavelength is short the frequency is high. 
Frequency determines the intensity of the wave. When high the frequencies are high the waves has more penetrating power, hence more powerful. 
GREYUIT [131]3 years ago
4 0

Answer:

More powerful

Explanation:

I answered it and got it right.

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Suppose the rocket in the Example was initially on a circular orbit around Earth with a period of 1.6 days. Hint (a) What is its
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Answer:

a

The orbital speed is v= 2.6*10^{3} m/s

b

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Explanation:

Generally angular velocity is mathematically represented as

            w = \frac{2 \pi}{T}

Where T is the period which is given as 1.6 days = 1.6 *24 *60*60 = 138240 sec

       Substituting the value

         w = \frac{2 \pi}{138240}

             = 4.54*10^ {-5} rad /sec

At the point when the rocket is on a circular orbit  

   The gravitational force =  centripetal force and this can be mathematically represented as

              \frac{GMm}{r^2} = mr w^2

Where  G is the universal gravitational constant with a value  G = 6.67*10^{-11}

            M is the mass of the earth with a constant value of M = 5.98*10^{24}kg

            r is the distance between earth and circular orbit where the rocke is found

               Making r the subject

                     r = \sqrt[3]{\frac{GM}{w^2} }

                        = \sqrt[3]{\frac{6.67*10^{-11} * 5.98*10^{24}}{(4.45*10^{-5})^2} }

                        = 5.78 *10^7 m

The orbital speed is represented mathematically as

                   v=wr

Substituting value

                  v= (5.78*10^7)(4.54*10^{-5})

                     v= 2.6*10^{3} m/s    

The escape velocity is mathematically represented as

                            v_e = \sqrt{\frac{2GM}{r} }

Substituting values

                             = \sqrt{\frac{2(6.67*10^{-11})(5.98*10^{24})}{5.78*10^7} }

                             v_e= 3.72 *10^3 m/s

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Given

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