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Finger [1]
2 years ago
12

Which term describes the amount of charge that passes a point in a circuit each second?

Physics
2 answers:
Flura [38]2 years ago
8 0

Answer:

volts

Explanation:

valentinak56 [21]2 years ago
3 0
The ampere is a measure of the amount of electric charge passing a point in an electric circuit per unit time, with an equivalent charge to 6.241×1018 charge carriers (or one coulomb) per second constituting one ampere. ... a path in which electrons from a voltage or current source flow.
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Identify the chemical change below
lesya [120]
Imma say go with C (:
5 0
3 years ago
A man is walking away from a lamppost with a light source h = 6 m above the ground. the man is m = 2 m tall. how long is the man
Llana [10]

Answer;

= 4 m is the length of the man's shadow.

Explanation;

2/x=6/(8+x) cross multiply.

6x=2(8+x)

6x=16+2x

6x-2x=16

4x=16

x=2=16/4

x=4 m. is the length of the man's shadow.

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3 years ago
Why won't a very bright beam of red light impart more energy to an ejected electron than a feeble beam of violet light?
bearhunter [10]
This is related to the energy carried by photons of light the energy of each photon is proportional to the frequency of the light since red light has a lower frequency then violet light and photons of red light carry less energy than the photons of violet light as a result the red protons eject electrons that have less energy than the ejected electrons by Violet photons
3 0
2 years ago
A very delicate sample is placed 0.150 cm from the objective lens of a microscope. The focal length of the objective is 0.140 cm
iVinArrow [24]

Answer:

m = 14*26 = 364

Explanation:

overall magnification is given as m

m = m_{o}* m_{e}

mo magnification of objective lens

me magnification of EYE lens

where mo is given as

m_{o} = \frac{v_{o}}{-u _{0}}

and me as

m_{e} = 1+\frac{D}{f_{e}}

d is distant of distinct vision = 25.0 cm for normal eye

fe =  focal length of eye piece

focal length of objective lense is 0.140 cm

we know that

\frac{1}{v_{0}}-\frac{1}{u_{0}}=\frac{1}{f_{0}}

\frac{1}{v_{0}} = \frac{1}{u_{0}} + \frac{1}{f_{0}}

\frac{1}{v_{0}} = \frac{1}{0.150} + \frac{1}{0.14}

\frac{1}{v_{o}} = 2.1 cm

m_{o} = \frac{2.1}{0.150} = 14

m_{e} = 1+\frac{25}{1}

m_{e} =26

m = m_{o}* m_{e}

m = 14*26 = 364

4 0
3 years ago
A perpendicular force is applied to a certain area and produces a pressure P. If the
Furkat [3]

Answer:

p/2

Explanation:

4 0
2 years ago
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