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777dan777 [17]
3 years ago
14

A bicyclist of mass 88.0 kg puts all his weight on each downward-moving pedal as he pedals up a steep road. Take the diameter of

the circle in which the pedals rotate to be 0.33 m, and determine the magnitude of the maximum torque he exerts in the process.
Physics
1 answer:
Eduardwww [97]3 years ago
3 0

Answer:

142.296 Nm.

Explanation:

Torque: This is the force that tend to cause a body to rotate or twist. The S.I unit of torque is Nm.

From the question,

T = F×r.................... Equation 1

Where T = Torque, F = Force, r = radius of the circle.

Note: F is the weight of the bicyclist.

Then,

F = W = mg............... Equation 2

Substitute equation 2 into equation 1

T = mgr................... Equation 3

Given: m = 88 kg, g = 9.8 m/s², r = 0.33/2 m

T = 88(9.8)(0.33)/2

T = 142.296 Nm.

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A major-league pitcher can throw a ball in excess of 40.1 m/s. If a ball is thrown horizontally at this speed, how much will it
mote1985 [20]

Answer:

The ball will drop 0.881 m by the time it reaches the catcher.

Explanation:

The position of the ball at time "t" is described by the position vector "r":

r = (x0 + v0x · t, y0 + v0y · t + 1/2 · g · t²)

Where:

x0 = initial horizontal position.

v0x = initial horizontal velocity.

t = time.

y0 = initial vertical position.

v0y = initial vertical velocity.

g = acceleration due to gravity (-9.8 m/s² considering the upward direction as positive).

When the ball reaches the catcher, the position vector will be "r final" (see attached figure).

The x-component of the vector "r final", "rx final", will be 17.0 m. We have to find the y-component.

Using the equation of the x-component of the position vector, we can calculate the time it takes the ball to reach the catcher (notice that the frame of reference is located at the throwing point so that x0 and y0 = 0):

x = x0 + v0x · t

17.0 m = 0 m + 40.1 m/s · t

t = 17.0 m/ 40. 1 m/s = 0.424 s

With this time, we can calculate the y-component of the vector "r final", the drop of the ball:

y = y0 + v0y · t + 1/2 · g · t²

Initially, there is no vertical velocity, then, v0y = 0.

y = 1/2 · g · t²

y = -1/2 · 9.8 m/s² · (0.424 s)²

y = -0.881 m

The ball will drop 0.881 m by the time it reaches the catcher.

8 0
3 years ago
Select all that apply.
GenaCL600 [577]

The correct answer to the question is: A) miles/hour and B) metre/ second.

EXPLANATION:

Before answering this question, first we have to understand speed.

The speed of a body is defined as the rate of distance travelled or the distance travelled by a body per unit time.

Hence, it is a derived quantity which is obtained from distance and time.

The unit of distance can be metre, miles, and the unit of time can be second, minutes or hour.

As speed is the distance covered per unit time, the perfect units will be miles/hour and metre/second.

Hence, the correct options are first and second.

5 0
3 years ago
Read 2 more answers
A wagon full of manure accidentally rolls down a driveway for 5.0m while a person pushes against the wagon with a force of 420 N
Cerrena [4.2K]

Answer:

2100 J

Explanation:

Parameters given:

Force acting on the object, F = 420 N

Distance moved by object, d = 5m

The change in kinetic energy of an object is equal to the work done by a force acting on the object:

W = F * d

∆KE = F * d

∆KE = 420 * 5

∆KE = 2100 J

8 0
3 years ago
Read 2 more answers
12. Unmanned Space Probe A 2500 kg unmanned space probe is moving in a straight line at a constant speed of 300 m/s. Control roc
Lena [83]

answer of both parts are attached below



4 0
3 years ago
Read 2 more answers
Please answer the one you know!
tresset_1 [31]
#8 positive kinetic energy
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2 years ago
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