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sertanlavr [38]
3 years ago
8

How much of the mass of the solar system is contained in the sun

Physics
1 answer:
Luda [366]3 years ago
6 0

Answer:

99.8 percent

can u help me with my questions i just ask go to my profile i just posted them

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-Dominant- [34]
Litres or millilitres
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A passenger plane is flying above the ground.Describe the two components of its mechanical enserfy
Goryan [66]
The force and the air resistance depends on the mechanical enserfy.
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3 years ago
Measurements on the cornea of a person's eye reveal that the magnitude of the front surface radius of curvature is while the mag
34kurt

(a) If the cornea were simply thin lens then power will be 43 diopters.

(b) This is a concave lens

The cornea is the transparent front part of the eye that covers the iris, pupil, and anterior chamber. Despite injury or disease, the cornea can still repair itself quickly. However, there are situations where damage is too severe for the cornea to heal on its own – such as with a deep injury to the cornea. The following symptoms may indicate that the cornea has sustained a substantial infection, injury or disease: Blurred vision Pain Redness.

Along with the anterior chamber and lens, the cornea refracts light, accounting for approximately two-thirds of the eye's total optical power. In humans, the refractive power of the cornea is approximately 43 diopters.

There are two types of lenses: converging and diverging and here if the cornea was simply thin then the diverging or concave lens is used in the eyes which is thin in the center than their edges.

To know more about cornea, refer: brainly.com/question/13866057

#SPJ4

5 0
1 year ago
calculate the distance in km that alex can run in 2.0 hours if she maintains the constant average speed of 8.00 km/h
Tema [17]
16 kilometers is the answer i came up with. hope this helps.
4 0
4 years ago
A spring with a spring constant of 50 N/m is stretched 15cm. What is the force and energy associated with this stretching?
Olenka [21]
Data:
F (force) = ? (Newton)
k (<span>Constant spring force) = 50 N/m
x (</span>Spring deformation) = 15 cm → 0.15 m

Formula:
F = k*x

Solving: 
F = k*x
F = 50*0.15
\boxed{\boxed{F = 7.5\:N}}\end{array}}\qquad\quad\checkmark

Data:
E (energy) = ? (joule)
k (Constant spring force) = 50 N/m
x (Spring deformation) = 15 cm → 0.15 m

Formula:
E = \frac{k*x^2}{2}

Solving:(Energy associated with this stretching)
E = \frac{k*x^2}{2}
E =  \frac{50*0.15^2}{2}
E =  \frac{50*0.0225}{2}
E =  \frac{1.125}{2}
\boxed{\boxed{E = 0.5625\:J}}\end{array}}\qquad\quad\checkmark

7 0
3 years ago
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