The Occupational Safety and Health Administration requires employers to provide fall protection to construction workers who are
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The wavelength of the sound wave if the frequency is increased to the given value is 0.44m.
Given the data in the question;
- Frequency of sound wave a;
- Wavelength of sound wave a;
Speed of sound wave;
- Frequency of sound wave b;
Wavelength of sound wave b;
Wavelength is simply the distance over which the shapes of waves are repeated. It is the spatial period of a periodic wave.
It is expressed as;
Where v is velocity and f is frequency.
First, we calculate the velocity of the sound wave in air from sound wave a.
Now, we determine the wavelength of sound wave b using the velocity of sound wave in air calculated above.
Therefore, the wavelength of the sound wave if the frequency is increased to the given value is 0.44m.
Learn more about wavelength: brainly.com/question/27120701
For this we will use kinematic equations.
We need the time of flight to compute the range.
With the given information, the most useful formula is:
Δy=v0yt−g2t2
Because our equation is taking only vertical motion into account,
v0y=30sin(45)
Because we are looking for the range of the object,
Δy=0
This leaves us with only one unknown: t
0=30sin(45)t−g2t2
g2t2=30sin(45)t
g2t=30sin(45)
t=60gsin(45)
For horizontal distance, the formula we need is:
Δx=v0xt
Because we are taking into account the horizontal range,
v0x=30cos(45)
In substituting our derived values into the equation we can see that:
Δx=30cos(45)∗60gsin(45)
Range=30cos(45)∗60gsin(45)
