Answer:
Electric flux;
Φ = 30.095 × 10⁴ N.m²/C
Explanation:
We are given;
Charge on plate; q = 17 µC = 17 × 10^(-6) C
Area of the plates; A_p = 180 cm² = 180 × 10^(-4) m²
Angle between the normal of the area and electric field; θ = 4°
Radius;r = 3 cm = 3 × 10^(-2) m = 0.03 m
Permittivity of free space;ε_o = 8.85 × 10^(-12) C²/N.m²
The charge density on the plate is given by the formula;
σ = q/A_p
Thus;
σ = (17 × 10^(-6))/(180 × 10^(-4))
σ = 0.944 × 10^(-3) C/m²
Also, the electric field is given by the formula;
E = σ/ε_o
E = (0.944 × 10^(-3))/(8.85 × 10^(-12))
E = 1.067 × 10^(8) N/C
Now, the formula for electric flux for uniform electric field is given as;
Φ = EAcos θ
Where A = πr² = π × 0.03² = 9π × 10^(-4) m²
Thus;
Φ = 1.067 × 10^(8) × 9π × 10^(-4) × cos 4
Φ = 30.095 × 10⁴ N.m²/C
Answer:
16.7 mF
Explanation:
The total capacitance of two capacitors connected in series is given by the formula:
in our problem, we have:
C1 = 45 mF is the capacitance of the first capacitor
C2 = 26 mF is the capacitance of the second capacitor
Substituting into the equation, we find:
Wavelength = (speed) / (frequency)
= (30 m/s) / (60/sec) =
= 0.5 meter .
Because the friction on the surface you are sliding on and the friction of the crate, go against each other. So once you start moving the friction will still be there but you now have the momentum to push past the starting point.
Orbit circumference
<span>= 2 pi *1.9*10^7 miles </span>
<span>time for orbit trip = 2.9*10^7 s </span>
<span>speed = 2 pi *1.9 / 2.9 miles/second </span>
<span>= 4.12 miles/second </span>
<span>You did not say what units </span>
<span>in miles per hour, multiply by 3600 and get </span>
<span>14,820 miles/hour</span>
