Answer: The first one goes under three, Second one goes in the third row, The third one goes in the third row also, I'm thinking the fourth one goes under the third row too, and I'm thinking the last one on the top goes in $1 per 2.5 ounces.
Step-by-step-exclamation : How I know this is because I did the math on my calculator and you can too to check my work ✔
Factor by groups
(Z^2 -6z) (-6z+36)
GCF 1st binomial is z
GCF of 2nd binomial is -6
(z-6)(z-6)
Solutions
6,6
Step-by-step explanation:
for 14 rides its 70 so you already don't have enough
<span>I am assuming the gender of each child is independent of the other.
Then the information about the first three children is irrelevant.
So then the probability of fourth child being boy is 1/2, since </span><span>boys and girls are equally likely</span><span>.
Hope this helps.</span>
Answer:
Step-by-step explanation:
I'm going to paint you a picture in words of what this looks like on paper. We have a train leaving from a point on your paper heading straight west. We have another train leaving from the same point on your paper heading straight east. This is the "opposite directions" that your problem gives you.
Now let's make a table:
distance = rate * time
Train 1
Train 2
We will fill in this table from the info in the problem then refer back to our drawing. It says that one train is traveling 12 mph faster than the other train. We don't know how fast "the other train" is going, so let's call that rate r. If the first train is travelin 12 mph faster, that rate is r + 12. Let's put that into the table
distance = rate * time
Train 1 r
Train 2 (r + 12)
Then it says "after 2 hours", so the time for both trains is 2 hours:
distance = rate * time
Train 1 r * 2
Train 2 (r + 12) * 2
Since distance = rate * time, the distance (or length of the arrow pointing straight west) for Train 1 is 2r. The distance (or length of the arrow pointing straight east) for Train 2 is 2(r + 12) which is 2r + 24. The distance between them (which is also the length of the whole entire arrow) is 232. Thus:
2r + 2r + 24 = 232 and
4r = 208 so
r = 52
This means that Train 1 is traveling 52 mph and Train 2 is traveling 12 miles per hour faster than that at 64 mph
