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4 years ago

3. The circuit below shows two outdoor lights, run by a battery. Four amps of

Physics

1 answer:

miv72 [106K]4 years ago

4 0

Answer:

The answer to your question is given below.

Explanation:

From the diagram given in the question, we can see that the bulbs are in parallel connection. This implies that different current will go through the bulb but the same voltage. But the resistance of each bulb is the same, therefore the same current current will go through them.

This can further be understood if we determine the current flowing through each bulb. This is illustrated below:

Voltage (V) = 30V

Resistant 1 (R1) = 15Ω

Current 1 (I1) =..?

V = I1R1

30 = I1 x 15

Divide both side by 15

I1 = 30/15

I1 = 2A.

Voltage (V) = 30V

Resistant 2 (R2) = 15Ω

Current 2 (I2) =..?

V = I2R2

30 = I2 x 15

Divide both side by 15

I2 = 30/15

I2 = 2A.

The overall current(I) in the circuit:

I = I1 + I2

I = 2 + 2 = 4A.

From the illustrations above, we can see that the same current will flow through each bulb as the will current split into two equal parts

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When a 40-n force, parallel to the incline and directed up the incline, is applied to a crate on a frictionless incline that is

Genrish500 [490]

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3 years ago

4. Describe how the velocity of an object changes if it undergoes uniformly acceleration motion. Can its direction change?

valentinak56 [21]

Answer:

n the case of linear motion, the change occurs in the magnitude of the velocity, the direction remaining constant.

In the case of circular motion, the magnitude of the velocity remains constant, the change in its direction occurring.

Explanation:

Velocity is a vector therefore it has magnitude and direction, a change in either of the two is the consequence of an acceleration on the system.

In the case of linear motion, the change occurs in the magnitude of the velocity, the direction remaining constant.

$a_{t}$ = (v₂-v₁)/Δt

In the case of circular motion, the magnitude of the velocity remains constant, the change in its direction occurring.

$a_{c}$ = v2/R

In the general case, both the module and the address change

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3 years ago

Help!!!

snow_lady [41]

Answer:

Explanation:

Hydrant

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3 years ago

Nick, a 60 kg physics student, wants to go bungee jumping, but doesn't have a bungee cord. He finds a 15 m long, strong spring (

vitfil [10]

Answer:

h = 24.81 m

Explanation:

Given:-

- The mass of the student, m = 60 kg

- The length of the spring, L = 15 m

- The spring constant, k = 60 N/m

Find:-

How far below the bridge is he hanging

Solution:-

- First realize that after the student attempts a bungee jump he oscillates violently ( dynamic motion ). After some time all the kinetic energy has been converted to Elastic and gravitational potential energy student is (stationary) and hanging down on one end of the spring.

- We will apply equilibrium condition on the student. We see that there are two forces acting on the student. The weight (W) of the student acting downward is in combat with the spring restoring force (Fs) acting upwards.

- Apply equilibrium condition in vertical direction:

Fs - W = 0

Fs = W

- The weight and spring force can be expressed as:

k*x = m*g

Where, g : Gravitational acceleration constant = 9.81 m/s^2

x : The extension of the spring from original position

- Solve for the extension (x) of the spring for this condition.

x = m*g / k

- Plug in the values and evaluate:

x = (60 kg)*(9.81 m/s^2) / (60 N/m)

x = 9.81 m

- The spring extends for about 9.81 m from its original length. So the distance (h) from edge of the bridge would be:

h = L + x

h = 15 + 9.81

h = 24.81 m

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3 years ago

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3 years ago