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Dahasolnce [82]
2 years ago
11

If Brett and Chris are trying to move a piano and Brett pushes the piano with 25 N of force and Chris pulls the piano in the sam

e direction with 20 N of force what is the net force
Physics
1 answer:
kirza4 [7]2 years ago
7 0

Answer:

45 N

Explanation:

From the question given above, the following data were obtained:

Force applied by Brett = 25 N

Force applied by Chris = 20 N

Net force =?

From the question given above, Brett and Chris applied force to the piano in the same direction. Thus the net force acting on the piano will be the sum of the forces applied by Brett and Chris. This can be obtained as follow:

Force applied by Brett = 25 N

Force applied by Chris = 20 N

Net force =?

Net force = 25 + 20

Net force = 45 N

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A Ferris wheel starts at rest and builds up to a final angular speed of 0.70 rad/s while rotating through an angular displacemen
PilotLPTM [1.2K]

Answer:

The average angular acceleration is 0.05 radians per square second.

Explanation:

Let suppose that Ferris wheel accelerates at constant rate, the angular acceleration as a function of change in angular position and the squared final and initial angular velocities can be clear from the following expression:

\omega^{2} = \omega_{o}^{2} + 2 \cdot \alpha\cdot (\theta-\theta_{o})

Where:

\omega_{o}, \omega - Initial and final angular velocities, measured in radians per second.

\alpha - Angular acceleration, measured in radians per square second.

\theta_{o}, \theta - Initial and final angular position, measured in radians.

Then,

\alpha = \frac{\omega^{2}-\omega_{o}^{2}}{2\cdot (\theta-\theta_{o})}

Given that \omega_{o} = 0\,\frac{rad}{s}, \omega = 0.70\,\frac{rad}{s} and \theta-\theta_{o} = 4.9\,rad, the angular acceleration is:

\alpha = \frac{\left(0.70\,\frac{rad}{s} \right)^{2}-\left(0\,\frac{rad}{s} \right)^{2}}{2\cdot \left(4.9\,rad\right)}

\alpha = 0.05\,\frac{rad}{s^{2}}

Now, the time needed to accelerate the Ferris wheel uniformly is described by this kinematic equation:

\omega = \omega_{o} + \alpha \cdot t

Where t is the time measured in seconds.

The time is cleared and obtain after replacing every value:

t = \frac{\omega-\omega_{o}}{\alpha}

If \omega_{o} = 0\,\frac{rad}{s},  \omega = 0.70\,\frac{rad}{s} and \alpha = 0.05\,\frac{rad}{s^{2}}, the required time is:

t = \frac{0.70\,\frac{rad}{s} - 0\,\frac{rad}{s} }{0.05\,\frac{rad}{s^{2}} }

t = 14\,s

Average angular acceleration is obtained by dividing the difference between final and initial angular velocities by the time found in the previous step. That is:

\bar \alpha = \frac{\omega-\omega_{o}}{t}

If \omega_{o} = 0\,\frac{rad}{s},  \omega = 0.70\,\frac{rad}{s} and t = 14\,s, the average angular acceleration is:

\bar \alpha = \frac{0.70\,\frac{rad}{s} - 0\,\frac{rad}{s} }{14\,s}

\bar \alpha = 0.05\,\frac{rad}{s^{2}}

The average angular acceleration is 0.05 radians per square second.

4 0
3 years ago
True or false When hydrogen joins with oxygen, a hydrogen bond has been formed.
ladessa [460]

Answer:

hydorgen bond

Explanation: pls give me branliest

8 0
3 years ago
Which of these are scientific questions? Check all that apply. How will climate change affect forests? Which planet is the prett
Naddika [18.5K]

Answer:

The scientific questions here are:

<em>a) How will climate change affect forests</em>

<em>b) How did life on Earth begin</em>

<em>c) Why did dinosaurs go extinct</em>

Explanation:

Scientific question are logical quantifiable questions, whose answers can be measured. A good scientific question must have answers that can be tested by a carefully designed experiment or measurement. Some qualities like "prettiest" and "amazing" cannot be tested for nor are they measurable, and hence, they do not make a testable component of good scientific question.

6 0
3 years ago
A 1200 kg sports car accelerates from 0 m/s to 30 m/s in 10 s. What is the average power of the engine?
DIA [1.3K]

Answer:

3600N

Explanation:

Given: m = 1200kg, Vo = 0m/s, Vf = 30m/s, Δt = 10s

ΣF = ma

we need to find 'a' first, using the definition of 'a' we get equation:

a = (Vf-Vo)/Δt

a = (30m/s)/10s

a = 3 m/s^2

now substitute into top equation

ΣF = ma

Fengine = (1200kg)(3m/s^2)

Fengine = 3600N

5 0
2 years ago
Read 2 more answers
you know that there are 1609 meter in a mile. the number of feet in a mile is 5280. what is the speed snail from problem 7 per m
Zanzabum

Answer:

We know that 1 meter = 100 centimeters, and 1 foot = 12 inches.

So  (1,609 meters) x (100 centimeters/meter)  =  (5,280 feet) x (12 inches/foot)

The second fraction on each side of the equation is equal to ' 1 ', because

the numerator is equal to the denominator, so sticking it in there doesn't

change the value of that side of the equation.  But now we can cancel some

units,and wind up with the units we need.

  (1,609 meters) x (100 centimeters/meter)  =  (5,280 feet) x (12 inches/foot)

        (1,609 x100) centimeters  =  (5,280 x 12) inches

            160,900 centimeters  =  63,360 inches

Divide each side by  63,360 :        2.54 centimeters =  1 inch

Explanation:

5 0
2 years ago
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