f(x) *g(x) = (x-3)(x+11) = x^2 +11x -3x -33 = x^2 +8x -33
Sorry if its wrong :(
Let the required point be (a,b)
The distance of (a,b) from (7,-2) is
= 
But this distance needs to be betweem 50 & 60
So
Squaring all sides
2500 < (a-7)² + (b+2)² < 3600
Let a = 7
So we have
2500 < (b+2)² <3600
b+2 < 60 or b+2 > -60 => b <58 or b > -62
Also
b+2 >50 or b + 2 < -50 => b >48 or B < -52
Let us take one value of b < 58 say b = 50
So now we have the point as (7, 50)
The other point is (7,-2)
Distance between them
= 
This is between 50 & 60
Hence one point which has a distance between 50 & 60 from the point (7,-2) is (7, 50)
6x5+24x3+3x3+12x ------> Simplify by adding like terms
6x5 + 27x3 + 12x
Note: I'm afraid I can't put the work for the answers, for lack of time =/
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1. 0 or -3
2. 0 or 4
3. -2 or 3
4. 0 or 1/2
5. -2 or 3
6. 0 or 5
7. 0 or 7
8. 0 or -2
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9. Substitute 0 for h in "h = -16x^2 + 16x" then solve for x
0 = -16x^2 + 16x
<span>Subtract -16x^2+16x from both sides.
</span><span>0−<span>(<span><span>−<span>16x2</span></span>+16x</span>)</span></span>=<span><span><span>−<span>16<span>x2</span></span></span>+<span>16x</span></span>−<span>(<span><span>−<span>16x2</span></span>+16x</span>)
</span></span><span><span>16<span>x2</span></span>−<span>16x</span></span>=<span>0
</span>
Factor the left side of the equation
<span><span>16x</span><span>(<span>x−1</span>)</span></span>=<span>0
</span>
Set factors to equal 0
<span><span>16x</span>=<span><span><span>0<span> or </span></span>x</span>−1</span></span>=<span>0
</span>x = 0 or x = 1
