Hello,
Please, see the attached files.
Thanks.
Please, see the attached files.
Thanks.
Help me to convert the following to redian (1) 300° (2)18° (3) 105°
1 answer:
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Answer:
For this case we can find the margin of error like this:
Since we need to divide the width of the interval by 2.
And now with the margin of error we can find the sample mean with any of the two following ways:
So for this case the correct answer would be:
A. Sample Mean = 13.7; Margin of Error = 1.1
Step-by-step explanation:
Previous concepts
A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".
The margin of error is the range of values below and above the sample statistic in a confidence interval.
Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".
Solution to the problem
The confidence interval for the mean is given by the following formula:
(1)
In order to calculate the critical value we need to find first the degrees of freedom, given by:
We know that the confidence interval is given by:
For this case we can find the margin of error like this:
Since we need to divide the width of the interval by 2.
And now with the margin of error we can find the sample mean with any of the two following ways:
So for this case the correct answer would be:
A. Sample Mean = 13.7; Margin of Error = 1.1
Answer:
Therefore the 95% confidence interval is (25,707.480 < E < 26,744.920)
Step-by-step explanation:
n = 77
mean u = 26,226.2 bushels per acre
standard deviation s = 2,322.32
let E = true mean
let A = test statistic
Find 95% Confidence Interval
so
let A = (u - E) * ( / s) be the test statistic
we want P( average_l < A < average_u ) = 95%
look for lower 2.5% and the upper 97.5% Because I think this is a 2-tail test
average_l = -1.96 which corresponds to the 2.5%
average_u = 1.96
P( -1.96 < A < 1.96) = 95%
P( -1.96 < (u - E) * ( / s) < 1.96) = 95%
Solve for the true mean E ok
E < u + 1.96* (s / )
from -1.96 < (u - E) * ( / s)
E < 26,226.2 + 1.96*( 2,322.32 / )
E < 26,226.2 + 1.96*( 2,322.32 / )
E < 26,226.2 + 518.7197348105429466
upper bound is 26,744.9197
or
u - 1.96* (s / ) < E
26,226.2 - 518.7197348105429466 < E
25,707.48026519 < E
lower bound is 25,707.48026519
Therefore the 95% confidence interval is (25,707.480 < E < 26,744.920)