Lol
trouble varies directly as distance
lets say t=trouble and d=distance
t=kd
k is constant
given
when t=20, and d=400
find k
20=400k
divide by 400 both sides
1/20=k
t=(1/20)d
given, d=60
find t
t=(1/20)60
t=60/20
t=3
3 troubles
Yes... a half is equal to 10/20 and 11/20 is greater than 10/20 so 11/20 is greater than a half
Answer:
3.0
Step-by-step explanation:
n=10
p=0.30
mean=np=10X0.3 = 3
That is it.
Answer:
(-5x)^4
Step-by-step explanation:
Answer:
Your picture didn't load?
Step-by-step explanation:
