<span>Let us first find a ratio between the quantity of work done by Darnell and Julius. If Darnell does one part of the work, Julius does two parts of the work. That is, their work quantity ratio is 1:2. (Total 3 parts) In other words when Darnell does 1/3 of the work, Julius does 2/3 of the work.
When they work together, the work is completed in 4 hours. 4 hours work is the combined output of 1/3 by Darnell and 2/3 by Julius. If Julius was not there, Darnell would have to work for more than 4 hours.
We already know that Darnell does only 1/3 of a work during any given time. If the given time is 4 hours, how many one-thirds will Darnell require? To find the answer, divide the given number (4 hours in this case) by the given fraction( 1/3 in this case) To divide a number by a fraction, multiply the number by the reciprocal of the fraction. Thus it becomes 4 divided by 1/3 = 4 x 3/1 = 12.
(Another hint: At the rate of 1/3 of a work in one hour, Darnell will needs 3 hours to complete the given task. If the given work is 4 hours long, Darnell will take 4 x 3 hours, that is 12 hours.)</span>
Answer:
B.alternative hypothesis
Step-by-step explanation:
In this case, the null hypothesis is that 45% of internet providers currently offer fiber optic internet in the United States.
The claim that the proportion of fiber optic internet providers is different from 45% is an alternative hypothesis since it directly contradicts the null hypothesis presented.
The answer is B. alternative hypothesis
How to get answer for number 1: | 4+2i |
![\left|a+bi\right|\:=\sqrt{\left(a+bi\right)\left(a-bi\right)}=\sqrt{a^2+b^2}\\\mathrm{With\:}a=4,\:b=2\\=\sqrt{4^2+2^2}\\Refine\\=\sqrt{20}\\\sqrt{20}=2\sqrt{5}\\=2\sqrt{5}](https://tex.z-dn.net/?f=%5Cleft%7Ca%2Bbi%5Cright%7C%5C%3A%3D%5Csqrt%7B%5Cleft%28a%2Bbi%5Cright%29%5Cleft%28a-bi%5Cright%29%7D%3D%5Csqrt%7Ba%5E2%2Bb%5E2%7D%5C%5C%5Cmathrm%7BWith%5C%3A%7Da%3D4%2C%5C%3Ab%3D2%5C%5C%3D%5Csqrt%7B4%5E2%2B2%5E2%7D%5C%5CRefine%5C%5C%3D%5Csqrt%7B20%7D%5C%5C%5Csqrt%7B20%7D%3D2%5Csqrt%7B5%7D%5C%5C%3D2%5Csqrt%7B5%7D)
How to get answer for number 2: | 5-i |
![\left|a+bi\right|\:=\sqrt{\left(a+bi\right)\left(a-bi\right)}=\sqrt{a^2+b^2}\\\mathrm{With\:}a=5,\:b=-1\\=\sqrt{5^2+\left(-1\right)^2}\\=\sqrt{26}](https://tex.z-dn.net/?f=%5Cleft%7Ca%2Bbi%5Cright%7C%5C%3A%3D%5Csqrt%7B%5Cleft%28a%2Bbi%5Cright%29%5Cleft%28a-bi%5Cright%29%7D%3D%5Csqrt%7Ba%5E2%2Bb%5E2%7D%5C%5C%5Cmathrm%7BWith%5C%3A%7Da%3D5%2C%5C%3Ab%3D-1%5C%5C%3D%5Csqrt%7B5%5E2%2B%5Cleft%28-1%5Cright%29%5E2%7D%5C%5C%3D%5Csqrt%7B26%7D)
Number 3 how to get answer: | -3i |
![\left|a+bi\right|\:=\sqrt{\left(a+bi\right)\left(a-bi\right)}=\sqrt{a^2+b^2}\\\mathrm{With\:}a=0,\:b=-3\\=\sqrt{0^2+\left(-3\right)^2}\\Refine\\=\sqrt{9}\\\sqrt{9}\\\mathrm{Factor\:the\:number:\:}\:9=3^2\\=\sqrt{3^2}\\\mathrm{Apply\:radical\:rule}:\quad \sqrt[n]{a^n}=a\\\sqrt{3^2}=3\\= 3](https://tex.z-dn.net/?f=%5Cleft%7Ca%2Bbi%5Cright%7C%5C%3A%3D%5Csqrt%7B%5Cleft%28a%2Bbi%5Cright%29%5Cleft%28a-bi%5Cright%29%7D%3D%5Csqrt%7Ba%5E2%2Bb%5E2%7D%5C%5C%5Cmathrm%7BWith%5C%3A%7Da%3D0%2C%5C%3Ab%3D-3%5C%5C%3D%5Csqrt%7B0%5E2%2B%5Cleft%28-3%5Cright%29%5E2%7D%5C%5CRefine%5C%5C%3D%5Csqrt%7B9%7D%5C%5C%5Csqrt%7B9%7D%5C%5C%5Cmathrm%7BFactor%5C%3Athe%5C%3Anumber%3A%5C%3A%7D%5C%3A9%3D3%5E2%5C%5C%3D%5Csqrt%7B3%5E2%7D%5C%5C%5Cmathrm%7BApply%5C%3Aradical%5C%3Arule%7D%3A%5Cquad%20%5Csqrt%5Bn%5D%7Ba%5En%7D%3Da%5C%5C%5Csqrt%7B3%5E2%7D%3D3%5C%5C%3D%203)
Answer:
5 pounds
Step-by-step explanation:
80 - 39.85 = 40.15
40.15 ÷ 8.03
= 5
Any with an odd number of minus signs.
Perhaps the 1st and 4th, if I read it right.