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zubka84 [21]
3 years ago
6

What is the surface area of a cylinder with a base radius of 3 ft and a height of 5ft

Mathematics
1 answer:
Solnce55 [7]3 years ago
6 0
SA of a cylinder: 2\pir² + 2\pirh
r = radius of base
h = height of cylinder

Plug in 3 for r and 5 for h in the formula.
2\pi3² + 2\pi(3)(5)
Use a calculator to solve.

2\pi3² + 2\pi(3)(5) = 150.8 ft²
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vodomira [7]
First solve the triangle:
75° + 75° + x = 180°
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x = 180° - 150°
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Then, use the geometrical property of vertically opposite angles.
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3 0
2 years ago
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The circumference of a sphere was measured to be 82 cm with a possible error of 0.5 cm.
Nat2105 [25]

Answer:

A) Maximum error = 170.32 cm³

B)Relative error = 0.0575

Step-by-step explanation:

A) Formula for circumference is: C = 2πr

Differentiating with respect to r, we have;

dC/dr = 2π

r is small, so we can write;

ΔC/Δr = 2π

So, Δr = ΔC/2π

We are told that ΔC = 0.5.

Thus; Δr = 0.5/2π = 0.25/π

Now, formula for Volume of a sphere is;

V(r) = (4/3)πr³

Differentiating with respect to r, we have;

dV/dr = 4πr²

Again, r is small, so we can write;

ΔS/Δr = 4πr²

ΔV = 4πr² × Δr

Rewriting, we have;

ΔV = ((2πr)²/π) × Δr

Since C = 2πr, we now have;

ΔV = (C²/π)Δr

ΔV will be maximum when Δr is maximum

Thus, ΔV = (C²/π) × 0.25/π

C = 82 cm

Thus;

ΔV = (82²/π) × 0.25/π

ΔV = 170.32 cm³

B) Formula for relative error = ΔV/V

Relative error = 170.32/((4/3)πr³)

Relative error = 170.32/((4/3)C³/8π³)

Relative errror = 170.32/((4/3)82³/8π³)

Relative error = 170.32/2963.744

Relative error = 0.0575

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2 years ago
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nexus9112 [7]

Answer:

Step-by-step explanation:

-5x + 10 > -15 is your original equation.

You need to isolate the x variable.

Start by subtracting 10.

-5x > -25

x > 5

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Answer: Hello, 6

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...

Step-by-step explanation:

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Answer:

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