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dlinn [17]
3 years ago
8

What is the source of energy used to react chlorine with methane?

Chemistry
2 answers:
Papessa [141]3 years ago
8 0
Ultraviolet light is the correct answer
Luden [163]3 years ago
5 0

Answer:

The source of energy used to react with chlorine and methane is ultraviolet rays or in the presence of sunlight.

Explanation:

The source of energy used to react with chlorine and methane is ultraviolet rays or in the presence of sunlight.This reaction is an example of Photo-chemical reaction.

Photo-chemical reaction is the type of chemical reaction in which energy is imparted to the reactants by the light or reactions initiated by light.

The photo chemical reaction of methane with chlorine in presence of ultraviolet light is given as:

CH_4+Cl_2\overset{h\nu}\rightarrow CH_3Cl+HCl

CH_3Cl+Cl_2\overset{h\nu}\rightarrow CH_2Cl_2+HCl

CH_2Cl_2+Cl_2\overset{h\nu}\rightarrow CH_1Cl_3+HCl

CH_1Cl_3+Cl_2\overset{h\nu}\rightarrow CCl_4+HCl

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Enter the balanced NET IONIC equation for the potentially unbalanced equation AgNO3(aq)+NaCl(aq)→AgCl(s)+NaNO3(aq).
Zigmanuir [339]

Answer:

Ag^+(aq)+Cl^-(aq)\rightarrow AgCl(s)

Explanation:

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In this case, since the net ionic equations are ionic representations of the molecular equation in which the spectator ions (those at both reactants and products sides) are cancelled out, we first write the complete ionic equation for this reaction, considering that the solid silver chloride is not ionized due to its precipitation:

Ag^+(aq)+NO_3^-(aq)+Na^+(aq)+Cl^-(aq)\rightarrow AgCl(s)+Na^+(aq)+NO_3^-(aq)

Whereas the nitrate and sodium ions are cancelled out for the aforementioned reason as they are the spectator ions, to obtain:

Ag^+(aq)+Cl^-(aq)\rightarrow AgCl(s)

Which is the required net ionic equation.

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4 0
3 years ago
This substance turns blue litmus paper red and reacts with metals to produce hydrogen gas?
djverab [1.8K]

Answer:

yes

Explanation:

yes

8 0
3 years ago
What happens to the atomic radius when an elctron is lost​
Daniel [21]

Answer:

It decreases.

Explanation:

Due to changes in the Coulombic force, the protons within the nucleus of the ion have a much easier time pulling at one fewer electrons. This way, the electrons are pulled closer to the center, causing the radius to decrease.

5 0
3 years ago
If there is a loss of 5.63 x 10-7kg of mass in a nuclear reaction, how many Joules of energy would be released? Recall that c =
Fudgin [204]
Thank you for posting your question here at brainly. 

E = mc^2 
<span>where E is the energy in joules, </span>
<span>m is the mass in kilograms, </span>
<span>and c is the speed of light. </span>

<span>E = mc^2 </span>
<span>E = (5.63 x 10^-7 kg)(3 x 10^8 m/s)^2 </span>
<span>E = 5.07 x 10^10 J </span>


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4 years ago
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Mumz [18]

Answer:

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Explanation:

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6 0
3 years ago
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