All categories

3 years ago

What new substance was made after they were mixed

Chemistry

1 answer:

Nataly [62]3 years ago

4 0

Answer:

In the baking soda and vinegar reaction, the new substances created are carbon dioxide gas, water, and something called sodium acetate. Carbon dioxide gas was inside the bubbles you saw. The detergent did not change in the reaction.

Explanation:

You might be interested in

A jet is goes from 180km/s to 139km/s in 22 seconds. What is it's acceleration?

jeyben [28]

180 km/s V= 25

explanation: i had the same assignment

5 0

3 years ago

A student did not read the direction to the experiment properly and mixed up where to place the NaOH solution and the vinegar. H

Mariana [72]

Answer:

At end point there will a transition from pink to colorless.

Explanation:

As the student put the vinegar in the titrator and NaOH in the beaker, it means that he has poured phenolphthalein in the NaOH solution.

The pH range of phenolphthalein is 8.3-10 (approx), it means it will show pink color in basic medium.

So on addition of phenolphthalein in NaOH the solution will become pink in color.

When we start pouring vinegar from titrator neutralization of NaOH will begin.

On complete neutralization , on addition of single drop of vinegar the solution will become acidic and there will be complete disappearance of pink color solution in the beaker.

3 0

4 years ago

The rate of a reaction is measured by how fast a reactant is used up to how fast a product is formed.

bezimeni [28]

A. True.

Very true. The quicker or slower the reactants are used up the faster or slower the rate of reaction, and the faster or slower the products are formed, the faster or slower the rate of reaction.

5 0

4 years ago

Read 2 more answers

How many milliliters of a 1M nitric acid solution are required to prepare 60mL of 6.7M solution?

Free_Kalibri [48]

Answer:

the number of milliliters of a 1M is 402mL

Explanation:

The computation of the number of milliliters could be determined by using the following formula

As we know that

$V_1\times M_1 = V_2\times M_2$

where,

V_1 and V_2 are the starting and final volumes

And, the M_1 and M_2 are the starting and the final molarities

Now the V_1 is

$V_1 \times 1M = 60mL \times 6.7M$

So, the V_1 is 402mL

Hence, the number of milliliters of a 1M is 402mL

4 0

3 years ago

1. Perform calculations to determine the amount of 6.00x10-5 M stock solution needed to prepare 20.00 mL of 2.00x10-5 M dye solu

zhannawk [14.2K]

Answer:

1a. 6.70 ml of stock dye solution is required

1b. 10.0 ml of stock dye solution is required

1c. 4.00 ml of stock dye solution is required

Explanation:

1a. Using m₁v₁ = m₂v

6.00 * 10⁻⁵ * v₁ = 20.0 * 2.00 * 10⁻⁵

v₁ = 4 * 10⁻⁴/6.00 * 10⁻⁵

v₁ = 6.70 mL of stock solution

Therefore, 6.70 ml of stock dye solution is required

b. Using m₁v₁ = m₂v

2.00 * 10⁻⁵ * v₁ = 20.0 * 1.00 * 10⁻⁵

v₁ = 2 * 10⁻⁴/2.00 * 10⁻⁵

v₁ = 10.0 mL of stock solution

Therefore, 10.0 ml of stock dye solution is required

c. Using m₁v₁ = m₂v

1.00 * 10⁻⁵ * v₁ = 20.0 * 2.00 * 10⁻⁶

v₁ = 4 * 10⁻⁵/1.00 * 10⁻⁵

v₁ = 4.00 mL of stock solution

Therefore, 4.00 ml of stock dye solution is required

The procedure is then followed as in steps 2 to 4.

4 0

3 years ago