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dezoksy [38]
3 years ago
8

The table compares some characteristics of two atoms.

Chemistry
2 answers:
11Alexandr11 [23.1K]3 years ago
5 0

Answer:

Atoms X and Atom Y are isotope is right answer

Tanya [424]3 years ago
3 0

Answer: Option (c) is the correct answer.

Explanation:

As it is known that mass number means the sum of total number of protons and neutrons present in an atom.

Whereas atomic number means only total number of protons.

As it is given that mass number of element X is 7 and neutrons present in it are 4. Hence, its atomic number will be calculated as follows.

                 Atomic number = Mass number - no. of neutrons

                                            = 7 - 4

                                            = 3

Now, it is given that mass number of element Y is 9 and neutrons present in it are 5. Hence, its atomic number will be calculated as follows.

                 Atomic number = Mass number - no. of neutrons

                                            = 9 - 5

                                            = 4

Therefore, atomic number of element X is 3 and atomic number of element Y is 4. So, it means both these elements are present in same period.

Thus, we can conclude that it is true about the two atoms that atom X and Atom Y are in the same row on the periodic table.  

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For the reaction below, Kp 5 1.16 at 800.8C. CaCO3(s) 34 CaO(s) 1 CO2(g) If a 20.0-g sample of CaCO3 is put into a 10.0-L contai
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Answer:

The mass percentage of calcium carbonated reacted is 2.5%.

Explanation:

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CaCO_{3}(s)--->CaO(s)+CO_{2}(g)

Thus the Kp of the equilibrium will be:

Kp = partial pressure of carbon dioxide [as the other are solid]

Moles of calcium carbonate initially present = \frac{mass}{molarmass}=\frac{20}{100}=0.2

Let us apply ICE table to the equilibrium given:

                        CaCO_{3}(s)--->CaO(s)+CO_{2}(g)

Initial                       0.2                       0          0

Change                 -x                            +x        +x

Equilibrium           0.2-x                         x          x

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Kp = Kc(RT)ⁿ

where n = difference in the number of moles of gaseous products and reactants

for given reaction n = 1

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T = temperature = 800 ⁰C = 1073 K

Putting values

Kc =\frac{Kp}{RT}=\frac{1.16}{8.314X1073}=1.3X10^{-4}

Kc = \frac{[CO_{2}][CaO]}{[CaCO_{3}]}= \frac{x^{2} }{(0.2-x)}=1.3X10^{-4}

1.3X10^{-4}(0.2-x)=x^{2}

x^{2} = 0.26X10^{-4}-1.3X10^{-4}x

On calculating

x =  0.005

where x = the moles of calcium carbonate dissociated or reacted.

Percentage of the moles or mass reacted = \frac{molesreacted X100}{initialmoles}=\frac{0.005X100}{0.2}=2.5%

7 0
3 years ago
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