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dezoksy [38]
3 years ago
8

The table compares some characteristics of two atoms.

Chemistry
2 answers:
11Alexandr11 [23.1K]3 years ago
5 0

Answer:

Atoms X and Atom Y are isotope is right answer

Tanya [424]3 years ago
3 0

Answer: Option (c) is the correct answer.

Explanation:

As it is known that mass number means the sum of total number of protons and neutrons present in an atom.

Whereas atomic number means only total number of protons.

As it is given that mass number of element X is 7 and neutrons present in it are 4. Hence, its atomic number will be calculated as follows.

                 Atomic number = Mass number - no. of neutrons

                                            = 7 - 4

                                            = 3

Now, it is given that mass number of element Y is 9 and neutrons present in it are 5. Hence, its atomic number will be calculated as follows.

                 Atomic number = Mass number - no. of neutrons

                                            = 9 - 5

                                            = 4

Therefore, atomic number of element X is 3 and atomic number of element Y is 4. So, it means both these elements are present in same period.

Thus, we can conclude that it is true about the two atoms that atom X and Atom Y are in the same row on the periodic table.  

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<u>Answer:</u> The boiling point of solution is 100.53

<u>Explanation:</u>

We are given:

8.00 wt % of CsCl

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Mass of solvent = (100 - 8) g = 92 grams

The equation used to calculate elevation in boiling point follows:

\Delta T_b=\text{Boiling point of solution}-\text{Boiling point of pure solution}

To calculate the elevation in boiling point, we use the equation:

\Delta T_b=iK_bm

Or,

\text{Boiling point of solution}-\text{Boiling point of pure solution}=i\times K_b\times \frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ (in grams)}}

where,

Boiling point of pure solution = 100°C

i = Vant hoff factor = 2 (For CsCl)

K_b = molal boiling point elevation constant = 0.51°C/m

m_{solute} = Given mass of solute (CsCl) = 8.00 g

M_{solute} = Molar mass of solute (CsCl) = 168.4  g/mol

W_{solvent} = Mass of solvent (water) = 92 g

Putting values in above equation, we get:

\text{Boiling point of solution}-100=2\times 0.51^oC/m\times \frac{8.00\times 1000}{168.4g/mol\times 92}\\\\\text{Boiling point of solution}=100.53^oC

Hence, the boiling point of solution is 100.53

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