a electron behavior is a subatomic particle whose electric i charge and the other one is a molecule and chemical bond that shares electrons
Answer:
Avogadro number of pennies will extend to a distance of 6.02 * 10¹⁷ km
<em>Note: The question is missing some parts. The complete question is as follows;</em>
<em>A penny has a thickness of approximately 1.0 mm . If you stack ed Avogadro's number of pennies one on top of the other on Earth 's surface, how far would the stack extend (in km)? [For comparison, the sun is about 150 million km from Earth and the nearest star (Proxim a Centauri) is about 40 trillion km from Earth.]</em>
Explanation:
Avogadro number = 6.02 * 10²³
thickness of a penny = 1.0 mm
I mm = 0.001 m
Thickness of Avogadro number of pennies stacked one upon another will be:
6.02 * 10²³ * 0.001 m = 6.02 * 10²⁰ m
Distance in km;
1 m = 0.001 km
therefore, 6.02 * 10²⁰ m = 6.02 * 10²⁰ * 0.001 km = 6.02 * 10¹⁷ km
Avogadro number of pennies will extend to a distance of 6.02 * 10¹⁷ km
<span> C12H4Cl6 + 23 O2 + 2 H2O → 24 CO2 + 12 HCl </span>
<span>(a) </span>
<span>(13.5 mol O2) x (2 mol H2O / 23 mol O2) = 1.17 mol H2O </span>
<span>(b) </span>
<span>(17.6 mol H2O) x (12 mol HCl / 2 mol H2O) x (36.4611 g HCl/mol) = 3850 g HCl </span>
<span>(c) </span>
<span>(90.4 g HCl) / (36.4611 g HCl/mol) x (24 mol CO2 / 12 mol HCl) = 4.96 mol CO2 </span>
<span>(d) </span>
<span>(106.01 g CO2) / (44.00964 g CO2/mol) x (2 mol C12H4Cl6 / 24 mol CO2) x (360.8782 g C12H4Cl6/mol) = </span>
<span>72.4 g C12H4Cl6 </span>
<span>(e) </span>
<span>(4.2 kg C12H4Cl6) / (360.8782 g C12H4Cl6/mol) x (12 mol HCl / 2 mol C12H4Cl6) x (36.4611 g HCl/mol) = </span>
<span>2.5 kg HCl</span>
Answer:
mass is 4.57 g
Explanation:
Ca(OH)₂ solution consists of Ca(OH)₂ solute molecules and solvent and we are asked to find the mass of Ca(OH)₂ in the solution
number of moles of Ca(OH)₂ is - 0.0787 mol
molar mass of Ca(OH)₂ is - 58.093 g/mol
we can use the following equation
number of moles = mass of Ca(OH)₂ / molar mass of Ca(OH)₂
rearranging the equation
mass of Ca(OH)₂ = number of moles x molar mass
mass = 0.0787 mol x 58.093 g/mol = 4.57 g
mass of Ca(OH)₂ is 4.57 g
