How are some mutations similar? Provide examples.
2 answers:
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Answer:
Moles of carbon atoms = 3.33 × mol
No. of atoms of C in Diamond = 2.007 × atom
Atoms of graphite = 6.27 × Atoms
Explanation:
given data
Cost of 0.2g of diamond = $5000
Cost of 25 g of graphite = $ 2
solution
we know cost of 0.2g of diamond is $ 5000 so that for 1$
if buy 1$ =
1$ = 4.0 × g Carbon
and Moles of carbon atoms is express as
Moles of carbon atoms = Given mass of Carbon ÷ atomic mass of C .........1
Moles of carbon atoms = 4.0 × g/ 2.0g
Moles of carbon atoms = 3.33 × mol
and
No. of atoms of C in Diamond = No. of moles × Avogadro NO ..............2
No. of atoms of C in Diamond = 3.33 × mol × 6.022 ×
No. of atoms of C in Diamond = 2.007 × atom
Graphite
and wew have given Cost of 25 g of graphite is $2 so for but 1$ we get
for buy $1 = 25÷2 = 12.5 g Of graphite
Moles of graphite = 12.5÷12 = 1.04 mol
Atoms of graphite = 1.04 × 6.022 × 1023
Atoms of graphite = 6.27 × Atoms