Problem 2
Plot point L anywhere that isn't on segment JK. Draw a line through point L. I find it helps to make the lines parallel.
Next, use a compass to measure the width of segment JK. Keeping this same width, transfer the nonpencil end of the compass to point L. Draw an arc that crosses the line through L.
Mark this intersection point M. Lastly, use a pen or marker to form segment LM and erase everything else of that line.
======================================================
Problem 3
The ideas of the previous problem will be used here. We copied segment JK to form congruent segment LM. So JK = LM.
The same steps will be used to form segment GN where GN = EF. In other words, segment GN is a perfect copy of segment EF.
If you repeat these steps again, you'll get another segment of the same length. This segment goes from point N to point H. So NH = GN = EF
Then we can say,
GH = GN + NH
GH = EF + EF
GH = 2*EF
Answer:
Is your teacher trying to confuse us or what?
Step-by-step explanation:
well 3/3 is full so it's just like 12/12, so 12 pieces of 1/12 piece are in 3/3
Answer:
(a) -6
Step-by-step explanation:
P(x) = ax^3 +bx - 3
- P(-1) = -a-b-3 = 0
- therefore a+b=-3
- P(1) = a+b-3
- P(1) = -3 - 3 = -6
- (a)
Answer:
18/5
Step-by-step explanation:
<em>From my understanding, this is 1 whole 2 upon 10</em>
<u>Step 1: Convert mixed fraction into fraction</u>
<em>Multiply whole number by denominator: 1 x 10 = 10</em>
<em>Add numerator: 10 + 2 = 12</em>
<em>Write the result as the numerator and use the same denominator.</em>
12/10
<u>Step 2: Find the total tape used</u>
<em>From my understanding, each student used 12/10 of the tap</em>
<em>So 3 students used: 12/10 x 3 =</em> 18/5
Therefore, the total tape used for three students was 18/5.
!!
The given equation is a wave function. When plotted, the graph is shown in the attached picture. However, the unit is in degrees instead of radians. A unit of π is equivalent to 180°. This plot could determine one variable if the other is given.
