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lana66690 [7]
2 years ago
14

If the scale factor of a figure is 6, what is the new length of the enlarged figure matched to the length of the

Mathematics
2 answers:
seraphim [82]2 years ago
7 0

Answer:

1=6

7=42

2.5=15

5=30

Step-by-step explanation:

Multiply each original value by the scale factor

1×6=6

7×6=42

2.5×6=15 (2×6 + 6×0.5)

5×6=30

kati45 [8]2 years ago
3 0

Answer:

Original: 5 cm = Enlarged: 30 cm

Original: 7 cm = Enlarged: 42 cm

Original: 2.5 cm = Enlarged: 15 cm

Original: 1 cm = Enlarged: 6 cm

Step-by-step explanation:

Edg Warm-up answer 2021

You might be interested in
If x = 7, what is the value of 3 times x²​
stira [4]

Answer:

147

Step-by-step explanation:

x = 7,

3x² = 3 × 7²

= 3 × 49

= 147

5 0
2 years ago
Claire bought 10 chicken nuggets for $17.00. If Claire spent $5.00, how many chicken nuggets did she buy
Ratling [72]

Answer

She would have 3.4 chicken nuggets i she spent $5 so she would have 3 chicken nuggets.

Step-by-step explanation:

17.00 divided by 5 = 3.4 or round down to 3.

                                                        hope it helps :b

6 0
3 years ago
How many pounds of cashew nuts worth 75 cents a pound must be mixed with 10 pounds of pecans worth $1.50 a pound to make a mixtu
Trava [24]
Let c represent the weight of cashews and p the weight of pecans.

Then c + 10 = total weight of the nut mixture.

An equation for the value of the mixture follows:

 $1.50(10 lb) + $0.75c = (c+10)($1.00)

Solve this equation for c:  15 + .75c = c + 10.  Subtract .75c from both sides:

15 = 1c - 0.75c + 10.  Then 5=0.25c, and c = 5/0.25, or 20.

Need 20 lb of cashews.


Check:  the pecans weigh 10 lb and are worth $1.50 per lb, so the total value of the pecans is $15.  The total value of the cashews is (20 lb)($0.75/lb), or $15.     Does (20 lb + 10 lb)($1/lb) = $15 + $15?  Yes.  So c= 20 lb is correct.
3 0
3 years ago
(6y + 3) minus (3y + 6) when y=7
never [62]

Answer:

y

Step-by-step explanation:

((((2•3y3) -  22y2) -  3y) -  —) -  2

                               y    

STEP

4

:

Rewriting the whole as an Equivalent Fraction

4.1   Subtracting a fraction from a whole

Rewrite the whole as a fraction using  y  as the denominator :

                      6y3 - 4y2 - 3y     (6y3 - 4y2 - 3y) • y

    6y3 - 4y2 - 3y =  ——————————————  =  ————————————————————

                            1                     y          

Equivalent fraction : The fraction thus generated looks different but has the same value as the whole

Common denominator : The equivalent fraction and the other fraction involved in the calculation share the same denominator

STEP

5

:

Pulling out like terms

5.1     Pull out like factors :

  6y3 - 4y2 - 3y  =   y • (6y2 - 4y - 3)

Trying to factor by splitting the middle term

5.2     Factoring  6y2 - 4y - 3

The first term is,  6y2  its coefficient is  6 .

The middle term is,  -4y  its coefficient is  -4 .

The last term, "the constant", is  -3

Step-1 : Multiply the coefficient of the first term by the constant   6 • -3 = -18

Step-2 : Find two factors of  -18  whose sum equals the coefficient of the middle term, which is   -4 .

     -18    +    1    =    -17

     -9    +    2    =    -7

     -6    +    3    =    -3

     -3    +    6    =    3

     -2    +    9    =    7

     -1    +    18    =    17

Observation : No two such factors can be found !!

Conclusion : Trinomial can not be factored

Adding fractions that have a common denominator :

5.3       Adding up the two equivalent fractions

Add the two equivalent fractions which now have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

y • (6y2-4y-3) • y - (6)     6y4 - 4y3 - 3y2 - 6

————————————————————————  =  ———————————————————

           y                          y        

Equation at the end of step

5

:

 (6y4 - 4y3 - 3y2 - 6)    

 ————————————————————— -  2

           y              

STEP

6

:

Rewriting the whole as an Equivalent Fraction :

6.1   Subtracting a whole from a fraction

Rewrite the whole as a fraction using  y  as the denominator :

        2     2 • y

   2 =  —  =  —————

        1       y  

Checking for a perfect cube :

6.2    6y4 - 4y3 - 3y2 - 6  is not a perfect cube

Trying to factor by pulling out :

6.3      Factoring:  6y4 - 4y3 - 3y2 - 6

Thoughtfully split the expression at hand into groups, each group having two terms :

Group 1:  -3y2 - 6

Group 2:  6y4 - 4y3

Pull out from each group separately :

Group 1:   (y2 + 2) • (-3)

Group 2:   (3y - 2) • (2y3)

Bad news !! Factoring by pulling out fails :

The groups have no common factor and can not be added up to form a multiplication.

Polynomial Roots Calculator :

6.4    Find roots (zeroes) of :       F(y) = 6y4 - 4y3 - 3y2 - 6

Polynomial Roots Calculator is a set of methods aimed at finding values of  y  for which   F(y)=0  

Rational Roots Test is one of the above mentioned tools. It would only find Rational Roots that is numbers  y  which can be expressed as the quotient of two integers

The Rational Root Theorem states that if a polynomial zeroes for a rational number  P/Q   then  P  is a factor of the Trailing Constant and  Q  is a factor of the Leading Coefficient

In this case, the Leading Coefficient is  6  and the Trailing Constant is  -6.

The factor(s) are:

of the Leading Coefficient :  1,2 ,3 ,6

of the Trailing Constant :  1 ,2 ,3 ,6

Let us test ....

  P    Q    P/Q    F(P/Q)     Divisor

     -1       1        -1.00        1.00    

     -1       2        -0.50        -5.88    

     -1       3        -0.33        -6.11    

     -1       6        -0.17        -6.06    

     -2       1        -2.00        110.00    

Note - For tidiness, printing of 13 checks which found no root was suppressed

Polynomial Roots Calculator found no rational roots

Adding fractions that have a common denominator :

6.5       Adding up the two equivalent fractions

(6y4-4y3-3y2-6) - (2 • y)      6y4 - 4y3 - 3y2 - 2y - 6

—————————————————————————  =  ————————————————————————

            y                            y            

Polynomial Roots Calculator :

6.6    Find roots (zeroes) of :       F(y) = 6y4 - 4y3 - 3y2 - 2y - 6

    See theory in step 6.4

In this case, the Leading Coefficient is  6  and the Trailing Constant is  -6.

The factor(s) are:

of the Leading Coefficient :  1,2 ,3 ,6

of the Trailing Constant :  1 ,2 ,3 ,6

Let us test ....

  P    Q    P/Q    F(P/Q)     Divisor

     -1       1        -1.00        3.00    

     -1       2        -0.50        -4.88    

     -1       3        -0.33        -5.44    

     -1       6        -0.17        -5.73    

     -2       1        -2.00        114.00    

Note - For tidiness, printing of 13 checks which found no root was suppressed

Polynomial Roots Calculator found no rational roots

Final result :

 6y4 - 4y3 - 3y2 - 2y - 6

 ————————————————————————

            y            

4 0
2 years ago
Read 2 more answers
What is the slope of the line shown in the graph? -1 -2 -1/2 2
MissTica

Answer:

The slope would would be -2

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
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