Answer:
(-4,-1)
Step-by-step explanation:
We are given T(1,2)=(-1,1) and T(1,-1)=(2,3) and T is a linear transformation.
This implies for scalars a and b that
T(a(1,2)+b(-1,1))=aT(1,2)+bT(-1,1)
T((a,2a)+(-b,b))=a(-1,1)+b(2,3)
T((a-b,2a+b))=(-a,a)+(2b,3b)
T((a-b,2a+b))=(-a+2b,a+3b)
This means we should be able to solve the system below to find a and b for T(3,3):
a-b=3 and 2a+b=3
Add equations to eliminate b and solve for a:
3a=6
Divide 3 on both sides:
a=2
If a-b=3 and a=2, then b=-1.
Plug in a=2, b=-1:
T((a-b,2a+b))=(-a+2b,a+3b)
T((2--1,2×2+-1)=(-2+2×-1,2+3×-1)
T(3,3)=(-4,-1).
which means 12 is the perpendicular & 37 is the hypotenuse [ Since Sin θ =
] . We're asked to find out tan θ ].
. Just plug the values :