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3 years ago

WILL MARK BRAINLIEST! What is the radius of a circle with a diameter of 21 meters?

Mathematics

2 answers:

trapecia [35]3 years ago

5 0

Answer:

10.5

Step-by-step explanation:

21 divided by 2=10.5

Olegator [25]3 years ago

4 0

Divide 21 by 2 and you’ll get 10.5 and That’s the answer

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The diagram above shows a rectangle inscribed in a circle AB=10 and AC =12 caculate the total surface area of the shaded part

erastova [34]

Answer:

$71.63 \: \: \mathrm{cm^2 }$

Step-by-step explanation:

Once we know the diameter of the circle, we can figure out the problem.

The diameter of the circle = The diagonal of the rectangle inscribed in the circle

To find the diagonal of the rectangle, we can use a formula.

$d=\sqrt{w^2 + l^2}$

The width is 10 cm and the length is 12 cm.

$d=\sqrt{10^2 + 12^2}$

$d \approx 15.62$

The diagonal of the rectangle inscribed in the circle is 15.62 cm.

The diameter of the circle is 15.62 cm.

Find the area of the whole circle.

$A=\pi r^2$

The $r$ is the radius of the circle, to find radius from diameter we can divide the value by 2.

$r = \frac{d}{2}$

$r=\frac{15.62}{2}$

$r=7.81$

Let’s find the area now.

$A=\pi (7.81)^2$

$A \approx 191.625$

Find the area of rectangle.

$A=lw$

Length × Width.

$A = 12 \times 10$

$A=120$

Subtract the area of the whole circle with the area of rectangle to find area of shaded part.

$191.625-120$

$71.625 \approx 71.63$

5 0

2 years ago

What is a equivalent ratio of 16:18

Elis [28]

equivalent ratio of 16:18 is 8:9

6 0

3 years ago

Read 2 more answers

Which of the following numbers could be the sides of a right triangle. A)8,15,17. B)6,8,12 C)9,11,21 D)4,13,16

ArbitrLikvidat [17]

Answer:

A) 8, 15, 17.

Step-by-step explanation:

Right triangle obey the Pythagorean theorem. Thus, we choose the two smaller numbers (being the cathetus) and if after applying the P. Theorem we get the biggest of each option (the hypotenuse) that means that those numbers could be the sides of a right triangle.

The Pythagorean theorem states that: $a^2+b^2=c^2$