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Tanya [424]
3 years ago
15

The discriminant of a quadratic equation is negative. One solution is 3+4i . What is the other solution?

Mathematics
2 answers:
Fiesta28 [93]3 years ago
4 0
I believe the correct answer from the choices listed above is option B. <span>The discriminant of a quadratic equation is negative. One solution is 3+4i . The other would be 3-4i. Hope this answers the question. Have a nice day.</span>
LenaWriter [7]3 years ago
3 0

Answer: Option B 3-4i is the correct option

Explanation:

we have formula for discriminant D=b^{2}-4ac

after that we find the required variable that is to be find according to the quadratic equation given suppose we have to find x

then we have formula x=\frac{-b\pm\sqrt{D}} {2a}

Here we have \pm of roots if we have one root 3+41 other would be of opposite sign and hence,definitely be 3-4i.

Therefore Option B 3-4i is the correct option.

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telo118 [61]

Answer:

1/8

Step-by-step explanation:

This is a compund probability problem. You need to find the probability of each event and then multiply the probabilities together.

The probability of flipping tails is 1/2. We need three of these.

1/2 x 1/2 x 1/2 = 1/8

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2 years ago
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3 years ago
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alexgriva [62]

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3 0
2 years ago
Read 2 more answers
Solve the triangle, AMDM
krok68 [10]

Answer:

B

Step-by-step explanation:

You are given two sides and the included angle, so you need to use the law of cosines.

c² = a² + b² - 2ab cos C

c² = 12² + 13² - 2(12)(13)cos 134°

c² = 313 - 312(-0.6947)

c² = 529.733

c = 23.016

Now use the law of sines.

c/sin C = a/sin A

23.016/sin 134° = 12/sin A

sin A = 12 × sin 134° / 23.016

sin A = 0.37504

A = 22.03°

B = 180° - 134° - 22.03°

B = 23.97°

m<A = 22°; m<B = 24°; c = 23 km

Answer: B

6 0
1 year ago
Claire Judice
Julli [10]

Answer:

The values of 'x' are -1.2, 0, 0, -4i or 4i.

Step-by-step explanation:

Given:

The equation to solve is given as:

5x^5+6x^4+80x^3+96x^2=0

Factoring x^2 from all the terms, we get:

x^2(5x^3+6x^2+80x+96)=0

Now, rearranging the terms, we get:

x^2(5x^3+80x+6x^2+96)=0

Now, factoring 5x from the first two terms and 6 from the last two terms, we get:

x^2(5x(x^2+16)+6(x^2+16))=0\\x^2(x^2+16)(5x+6)=0

Now, equating each factor to 0 and solving for 'x', we get:

x^2=0\\x=0\ and\ 0\\\\5x+6=0\\x=\frac{-6}{5}=1.2\\\\x^2+16=0\\x^2=-16\\x=\sqrt{-16}=\pm 4i

There are 3 real values and 2 imaginary values. The value of 'x' as 0 is repeated twice.

Therefore, the values of 'x' are -1.2, 0, 0, -4i or 4i.

4 0
3 years ago
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