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Serggg [28]
4 years ago
11

When work is done by a system and no heat is added, the temperature of the system?

Physics
1 answer:
Gnoma [55]4 years ago
3 0
The temperature would be just right
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What iz inertia ? -,-​
kipiarov [429]

Inertia refers to the tendency of a body to resist changes.

<h3>Inertia</h3>

It is the property of a body to resist change.

A moving body will continue moving until a force acts on it. Unless the acting force is big enough to overcome the inertia of the body, the body will continue moving.

Also, a body at rest will continue resting unless a force big enough to overcome the inertia force is used to displace it.

More on inertia can be found here: brainly.com/question/1358512

4 0
2 years ago
Read 2 more answers
I need help with physics. Question 3 and 4. Thanks.
shusha [124]
It’s c and a I believe ask someone else to make sure but I’m pretty sure
6 0
3 years ago
Generators are device that convert_____energy into____energy
KiRa [710]

Answer:

A generator converts mechanical energy into electrical energy, while a motor does the opposite - it converts electrical energy into mechanical energy.

Explanation:

5 0
4 years ago
Suppose we want to calculate the moment of inertia of a 56.5 kg skater, relative to a vertical axis through their center of mass
kirza4 [7]

Answer:

a. 0.342 kg-m² b. 2.0728 kg-m²

Explanation:

a. Since the skater is assumed to be a cylinder, the moment of inertia of a cylinder is I = 1/2MR² where M = mass of cylinder and r = radius of cylinder. Now, here, M = 56.5 kg and r = 0.11 m

I = 1/2MR²

= 1/2 × 56.5 kg × (0.11 m)²

= 0.342 kgm²

So the moment of inertia of the skater is

b. Let the moment of inertia of each arm be I'. So the moment of inertia of each arm relative to the axis through the center of mass is (since they are long rods)

I' = 1/12ml² + mh² where m = mass of arm = 0.05M, l = length of arm = 0.875 m and h = distance of center of mass of the arm from the center of mass of the cylindrical body = R/2 + l/2 = (R + l)/2 = (0.11 m + 0.875 m)/2 = 0.985 m/2 = 0.4925 m

I' = 1/12 × 0.05 × 56.5 kg × (0.875 m)² + 0.05 × 56.5 kg × (0.4925 m)²

= 0.1802 kg-m² + 0.6852 kg-m²

= 0.8654 kg-m²

The total moment of inertia from both arms is thus I'' = 2I' = 1.7308 kg-m².

So, the moment of inertia of the skater with the arms extended is thus I₀ = I + I'' = 0.342 kg-m² + 1.7308 kg-m² = 2.0728 kg-m²

5 0
3 years ago
What is the application of physics<br>​
arsen [322]

Answer:

1) We can estimate the age of the earth

2) we can calculate the speed of anything

3) we can also calculate gravity, e.t.c.

Explanation:

I could give you more just ask

4 0
4 years ago
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