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Helen [10]
3 years ago
12

An iron bal of mass 20kg is rolling on a flat surface. On applying force, the velocity change from 17ms to 27m/s in 5s. Calculat

e the magnitude of the force. (Ans:40N)
Physics
1 answer:
pentagon [3]3 years ago
4 0

Answer:

40 N

Explanation:

We first need to calculate the acceleration of the tron ball.

Since acceleration, a = (v - u)/t where u = initial velocity of iron ball = 17m/s, v = final velocity of iron ball = 27m/s and t = time taken for the change in velocity = 5 s.

So, a = (v - u)/t

= (27 m/s - 17 m/s)/5 s

= 10 m/s ÷ 5 s

= 2 m/s²

We know force on iron ball, F = ma where m = mass of iron ball = 20 kg and a = acceleration = 2 m/s²

So, F = ma

= 20 kg × 2 m/s²

= 40 kgm/s²

= 40 N

So, the magnitude of the force on the iron ball is 40 N.

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What is the change in thermal energy E if the coefficent of kinetic friction between the box and floor is .4 , the distance the
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This question can be solved using the concept of friction energy.

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The change in thermal energy will be equal to the friction energy produced during the motion of the box.

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where,

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Learn more about friction energy here:

brainly.com/question/1343045?referrer=searchResults

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3 years ago
For a Physics course containing 10 students, the maximum point total for the quarter was 200. The point totals for the 10 studen
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Answer:

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Explanation:

According to the stemplot attached (Which I think it is, and if not, then you only need to replace the procedure with your data and you should be fine), you need to calculate first the points of all ten students. In that plot, we can easily calculate the points.

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This means that the point for the students are 168, 165 and 166. Three students, three points.

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