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Mariana [72]
3 years ago
8

To get an idea of how much thermal energy is contained in the world's oceans, estimate the heat liberated when a cube of ocean w

ater, 3 km on each side, is cooled by 4 K. (Approximate the ocean water as pure water for this estimate.)
Physics
1 answer:
kolbaska11 [484]3 years ago
5 0

Answer:

Q = 4.52 10¹⁷ J

Explanation:

Thermal energy can be calculated with  

      Q = m c_{e} ΔT

in this case it indicates that we approximate seawater to pure water with  

    c_{e} = 4186 J/ kg K  

with the density

    ρ = m / V  

    m = ρ V  

    V = L³  

we substitute  

   m = ρ L³  

   Q = ρ L3 c_{e} ΔT

calculate  

   Q = 1000 (3 103) 3 4186 4  

   Q = 4.52 10¹⁷ J

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Answer:

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Explanation:

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You're answer is B. P waves are more dynamic and have a great autonomy to be able generate a earthquake.
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4 years ago
The two speakers at S1 and S2 are adjusted so that the observer at O hears an intensity of 6 W/m² when either S1 or S2 is sounde
Zanzabum

Answer:

The minimum frequency is 702.22 Hz

Explanation:

The two speakers are adjusted as attached in the figure. From the given data we know that

S_1 S_2=3m

S_1 O=4m

By Pythagoras theorem

                                 S_2O=\sqrt{(S_1S_2)^2+(S_1O)^2}\\S_2O=\sqrt{(3)^2+(4)^2}\\S_2O=\sqrt{9+16}\\S_2O=\sqrt{25}\\S_2O=5m

Now

The intensity at O when both speakers are on is given by

I=4I_1 cos^2(\pi \frac{\delta}{\lambda})

Here

  • I is the intensity at O when both speakers are on which is given as 6 W/m^2
  • I1 is the intensity of one speaker on which is 6  W/m^2
  • δ is the Path difference which is given as

                                           \delta=S_2O-S_1O\\\delta=5-4\\\delta=1 m

  • λ is wavelength which is given as

                                             \lambda=\frac{v}{f}

      Here

              v is the speed of sound which is 320 m/s.

              f is the frequency of the sound which is to be calculated.

                                  16=4\times 6 \times cos^2(\pi \frac{1 \times f}{320})\\16/24= cos^2(\pi \frac{1f}{320})\\0.667= cos^2(\pi \frac{f}{320})\\cos(\pi \frac{f}{320})=\pm0.8165\\\pi \frac{f}{320}=\frac{7 \pi}{36}+2k\pi \\ \frac{f}{320}=\frac{7 }{36}+2k \\\\ {f}=320 \times (\frac{7 }{36}+2k )

where k=0,1,2

for minimum frequency f_1, k=1

                                  {f}=320 \times (\frac{7 }{36}+2 \times 1 )\\\\{f}=320 \times (\frac{79 }{36} )\\\\ f=702.22 Hz

So the minimum frequency is 702.22 Hz

5 0
3 years ago
. What is the single most important equation in all of physics?​
vivado [14]

Answer: F = ma,

Explanation:

the most famous equation in physics, establishing an equivalence between energy and mass. But is this the most important equation in physics? Knowledgeable scientists will tell you no. The most important equation in physics is F = ma, also known as Newton's second law of mechanics.

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Answer:

fggdfddvdghyhhhhggghh

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