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3 years ago

What is 4.373 ×10^10 in standard notation

Mathematics

1 answer:

Lera25 [3.4K]3 years ago

3 0

Your answer is:
43,730,000,000
Hope this helps!=)

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ASAP PLEAE HELP

Licemer1 [7]

Answer:

21.801

Good luck

5 0

2 years ago

What is the measure of the missing exterior angle?

larisa86 [58]

Answer:

the missing angle is 148°

Step-by-step explanation:

the sum of all exterior angles of a triangle are 360°

so, 360-138-74 = 148°

3 0

2 years ago

Given the right triangle shown below.if Cos A =15/17 and tan A=8/15 which of the following represents the length of BC

otez555 [7]

Answer:

The Figure for Right triangle is below,

Therefore , 15 unit length represents BC.

Step-by-step explanation:

Given:

Consider a right triangle ABC, Such that

$\cos A=\dfrac{15}{17}\\\\\tan A=\dfrac{8}{15}$

To Find:

BC = ?

Solution:

In Right Angle Triangle ABC, Cosine and Tangent identity

$\cos A = \dfrac{\textrm{side adjacent to angle C}}{Hypotenuse}\\$

$\tan A= \dfrac{\textrm{side opposite to angle A}}{\textrm{side adjacent to angle A}}$

BUT,

$\cos A=\dfrac{15}{17}\\\\\tan A=\dfrac{8}{15}$ ....Given

On Comparing,

Adjacent side to angle A = AB = 15

Opposite side to angle A = BC = 8

Hypotenuse = AC =17

Also Pythagoras theorem is Satisfies,

$(\textrm{Hypotenuse})^{2} = (\textrm{Shorter leg})^{2}+(\textrm{Longer leg})^{2}$

$(\textrm{Hypotenuse})^{2} = 17^{2}=289$

$(\textrm{Shorter leg})^{2}+(\textrm{Longer leg})^{2}=15^{2}+8^{2}=289$

The Figure for Right triangle is below,

Therefore , 15 unit length represents BC.

7 0

2 years ago

I need help with geometry. Find x.

I am Lyosha [343]

Answer:

Part 9) $x=5$

Part 10) $x=-9$

Step-by-step explanation:

we know that

The Midpoint Theorem states that: The segment joining two sides of a triangle at the midpoints of those sides is parallel to the third side and is half the length of the third side

Part 9) we know that

Point Q is the midpoint segment XY (QY=QX)

Point R is the midpoint segment XW (RW=RX)

Applying the Midpoint Theorem

RQ is parallel to WY

and

$RQ=\frac{1}{2}WY$

we have

$RQ=2x-3\\WY=x+9$

substitute

$2x-3=\frac{1}{2}(x+9)$

solve for x

$4x-6=(x+9)$

$4x-x=9+6$

$3x=15$

$x=5$

Part 10) we know that

Point B is the midpoint segment TS (BS=BT)

Point C is the midpoint segment RS (CS=CR)

Applying the Midpoint Theorem

BC is parallel to TR

and

$BC=\frac{1}{2}TR$

we have

$BC=x+19\\TR=x+29$

substitute

$x+19=\frac{1}{2}(x+29)$

solve for x

$2x+38=(x+29)$

$2x-x=29-38$

$x=-9$

5 0

3 years ago

What is the mean of the data set [3, 2, 2, 12, 6, 5, 14, 4]? A: 2 B: 4 C: 6 D: 7

Semenov [28]

Answer: C.

Step-by-step explanation: 3+2+2+12+6+5+14+4=48 divided by 8 equals 6

3 0

2 years ago