Find the axis of symmetry and vertex of the following y= -2x2-3x+2

1 answer:

8 0

Y= -2x²-3x+2, (form y = ax² +b .x + c

The parabola opens downward & hence it's Vertex is a MAXIMUM.

We know that the axis of symmetry is -b/2a ==>3/(-4) ==>
x= - 3/4 (axis of symmetry. At x=-3/4 , y = 25/8 = 3.125

Hence the axis of symmetry is x= - 3/4 & the vertex is at (-3/4, 25/8)

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