Find the axis of symmetry and vertex of the following y= -2x2-3x+2
1 answer:
Y= -2x²-3x+2, (form y = ax² +b .x + c
The parabola opens downward & hence it's Vertex is a MAXIMUM.
We know that the axis of symmetry is -b/2a ==>3/(-4) ==>
x= - 3/4 (axis of symmetry. At x=-3/4 , y = 25/8 = 3.125
Hence the axis of symmetry is x= - 3/4 & the vertex is at (-3/4, 25/8)
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It depends on the size of each angle. If a parallelogram has the same sizes of the quadrilateral then they could both be congruent.
Hope this helps! :D
SRVUT is the correct one im pretty sure
Answer:
Step-by-step explanation:
4⋅ (4 + (2^6 ⋅ 2^−3))
= 4⋅ (4 + (64 ⋅ 1/8))
= 4⋅ (4 + 8)
= 4⋅ (12)
= 48
Answer is A. 48
Answer:
Simplify the expression.
13
x
3
+
3
x
2
+
1
Step-by-step explanation: