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Damm [24]
3 years ago
6

Find the axis of symmetry and vertex of the following y= -2x2-3x+2

Mathematics
1 answer:
Mnenie [13.5K]3 years ago
8 0
Y= -2x²-3x+2, (form y = ax² +b .x + c

The parabola opens downward & hence it's Vertex is a MAXIMUM.

We know that the axis of symmetry is -b/2a ==>3/(-4) ==>
x= - 3/4 (axis of symmetry. At x=-3/4 , y = 25/8 = 3.125

Hence the axis of symmetry is x= - 3/4 & the vertex is at (-3/4, 25/8)
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The sum of a number b and 3 is greater than 8 and less than 12 <span>=> b + 3 < 8
=> b + 3 > 12

</span> <span>Now, let’s combine this into an expression:
=> 8 < b+3 < 12
=>  (8 - 3) < b < (12 - 3)
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