Find the solid angle made by the part of surface area 2 cm square of square and radius 4 centimetre

Heat is:_________

zysi [14]

Answer:

The answer is C ..

EXPLANATION:-

The amount of energy transferred between objects as a result of a difference in temperature.

4 0

2 years ago

You are standing on a sheet of ice that covers the football stadium parking lot in Buffalo; there is

Arlecino [84]

Answer:

a) $v=0.5405\ m.s^{-1}$

b) $v_p'=0.1143\ m.s^{-1}$

Explanation:

Given:

mass of ball, $m_b=4\ kg$

initial speed of the ball, $v_b=10\ m.s^{-1}$

mass of the person, $m_p=70\ kg$

a)

Using the conservation of linear momentum:

When the person catches the ball, assuming that the person catches it with an impact without absorbing the shock.

$m_b.v_b=(m_b+m_p)v$

$4\times 10=(4+70)\times v$

$v=0.5405\ m.s^{-1}$

b)

When the ball hits the person and bounces off with the velocity of $v_b'=8\ m.s^{-1}$ .

Using the conservation of linear momentum:

$m_b.v_b+m_p.v_p=m_b.v_b'+m_p.v_p'$

where:

$v_b'=$ final speed of the ball after collision

$v_p'=$ final speed of the person after collision

$v_p=$ initial velocity of the person = 0

putting the respective values in the above eq.

$4\times 10+0=4\times 8+70\times v_p'$

$v_p'=0.1143\ m.s^{-1}$

8 0

3 years ago

Read 2 more answers

Which of the following equations describes Newton’s second law

svp [43]

C.

Newton’s Second Law is F=ma (force is equal to the mass multiplied by acceleration), however, the equation can be rearranged to isolate and calculate mass from force over acceleration. Therefore, m=F/a

8 0

2 years ago

Read 2 more answers

A heat pump is to be used for heating a house in winter. The house is to be maintained at 70°F at all times. When the temperatur

Anna35 [415]

Answer:

$\dot{W_{H} } = 4244.48 Btu/h$

Explanation:

Temperature of the house, $T_{H} = 70^{0} F$

Convert to rankine, $T_{H} = 70^{0}+ 460 = 530 R$

Heat is extracted at 40°F i.e $T_{L} = 40^{0}F = 40 + 460 = 500 R$

Calculate the coefficient of performance of the heat pump, COP

$COP = \frac{T_{H} }{T_{H} - T_{L} } \\COP = \frac{530 }{530 - 500 }\\ COP = \frac{530}{30} \\COP = 17.67$

The minimum power required to run the heat pump is given by the formula:

$\dot{W_{H} } = \frac{\dot{Q_{H} }}{COP} \\$ ...............(*)

Where the heat losses from the house, $\dot{Q_{H} } = 75,000 Btu/h$

Substituting these values into * above

$\dot{W_{H} } = \frac{75000}{17.67} \\ \dot{W_{H} } = 4244.48 Btu/h$

3 0

2 years ago

A 20.0-N weight slides down a rough inclined plane which makes an angle of 30 degree with the horizontal. The weight starts from

Ulleksa [173]

Answer:

$1270.64\ \text{J}$

Explanation:

m = Mass of object = $\dfrac{mg}{g}$

mg = Weight of object = 20 N

g = Acceleration due to gravity = $9.81\ \text{m/s}^2$

v = Final velocity = 15 m/s

u = Initial velocity = 0

d = Distance moved by the object = 150 m

$\theta$ = Angle of slope = $30^{\circ}$

f = Force of friction

fd = Work done against friction

The force balance of the system is

$\dfrac{1}{2}m(v^2-u^2)=(mg\sin\theta-f)d\\\Rightarrow \dfrac{1}{2}mv^2=mg\sin\theta d-fd\\\Rightarrow fd=mg\sin\theta d-\dfrac{1}{2}mv^2\\\Rightarrow fd=20\times \sin 30^{\circ}\times 150-\dfrac{1}{2}\times \dfrac{20}{9.81}\times 15^2\\\Rightarrow fd=1270.64\ \text{J}$

The work done against friction is $1270.64\ \text{J}$ .

8 0

3 years ago

Find the solid angle made by the part of surface area 2 cm square of square and radius 4 centimetre​

Find the solid angle made by the part of surface area 2 cm square of square and radius 4 centimetre