Find the solid angle made by the part of surface area 2 cm square of square and radius 4 centimetre

A beam of light has a wavelength of 620 nm in vacuum.

crimeas [40]

Explanation:

It is given that,

Wavelength of a beam of light in vacuum, $\lambda_o=620\ nm$

(a) Let v is the speed of light in a liquid whose index of refraction at this wavelength is 1.56.

We know that,

Refractive index,

$n=\dfrac{c}{v}\\\\v=\dfrac{c}{n}\\\\v=\dfrac{3\times 10^8}{1.56}\\\\v=1.92\times 10^8\ m/s$

(b) The wavelength of light in material,

$\lambda=\dfrac{\lambda_o}{n}$

Let $\lambda_1$ is the wavelength of these waves in the liquid. So,

$\lambda_1=\dfrac{\lambda_o}{n}\\\\\lambda_1=\dfrac{620\times 10^{-9}}{1.56}\\\\\lambda_1=3.97\times 10^{-7}\ m$

Hence, this is the required solution.

7 0

4 years ago

Describe scalar and vector quantities. Include a definition and provide at least one example of how they are alike and how they

Lunna [17]

Scalar quantities have only magnitude. example temperature, distance.

Vector quantities have magnitude and direction.Example force, velocity.

You can say "I applied a force p\of 3 newtons to the left" but you can't say I added 32 Fahrenheit to the left

8 0

3 years ago

Three identical very dense masses of 7500 kg each are placed on the x axis. One mass is at x1 = -100 cm , one is at the origin,

sukhopar [10]

Answer:

0.00354 (N)

Explanation:

Convert to metric system:

$x_1 = -100 cm = 1 m$

$x_2 = 420 cm = 4.2 m$

Formula for gravitational force:

$F_g = G\frac{mM}{s^2}$

where s is the distance between 2 bodies masses m and M

Substitute the number to the formula above and since the 2 forces are acting in opposite direction, the total net gravitational force on the mass of origin be:

$F_g = F_{g1} - F_{g2}$

$F_g = G\frac{m_1M}{x_1^2} - G\frac{m_2M}{x_2^2}$

$F_g = GM(\frac{m_1}{x_1^2} - \frac{m_2}{x_2^2})$

$F_g = 6.67*10^{-11} * 7500 (\frac{7500}{1^2} - \frac{7500}{4.2^2})$

$F_g = 5*10^{-7}(7500 - 425.17)$

$F_g = 5*10^{-7} * 7074.83$

$F_g = 0.00354 (N)$

5 0

3 years ago

Determine the centripetal force on a vehicle rounding a circular curve with a radius of 80 m at a constant speed of 90 km/h if t

quester [9]

Mass of the vehicle = 2000 kg
Velocity of the vehicle = 90 km/hr
= 25 m/s
Radius of the curve = 80 m
Then
Centripetal force = [2000 * (25)^2]/80
= (2000 * 625)/80
= 15625 kg m/s
= 15625 Newton second
I hope that this is the answer that you were looking for and the answer has come to your desired help.

3 0

3 years ago

Assume that you are considering the purchase of a 20-year, noncallable bond with an annual coupon rate of 9.5%. The bond has a f

DiKsa [7]

Answer:

$1,105.69

Explanation:

For this question we use the Present value formula that is shown on the attachment. Kindly find it below:

Given that,

Future value = $1,000

Rate of interest = 8.4% ÷ 2 = 4.2%

NPER = 20 years × 2 = 40 years

PMT = $1,000 × 9.5% ÷ 2 = $47.50

The formula is shown below:

= -PV(Rate;NPER;PMT;FV;type)

So, after solving this, the maximum price pay for the bond is $1,105.69

5 0

3 years ago

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Find the solid angle made by the part of surface area 2 cm square of square and radius 4 centimetre​

Find the solid angle made by the part of surface area 2 cm square of square and radius 4 centimetre