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evablogger [386]
3 years ago
15

When you take your 1900-kg car out for a spin, you go around a corner of radius 53m with a speed of 13m/s. The coefficient of st

atic friction between the car and the road is 0.88. Assuming your car doesnt skid, what is the force exerted on it by static friction?
Physics
1 answer:
anastassius [24]3 years ago
3 0

Answer:

Ff = 6058.5N

Explanation:

The sum of forces is:

Ff = m*a_c

Ff = m*V^2/R

Ff = 1900*13^2/53

Ff = 6058.5N

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WILL GIVE BRAINLIEST AND 50 POINTS!
7nadin3 [17]

Answer:

1) Current decreases; 2) Inverse proportionally; 3) 1[A]

Explanation:

1)

As we can see as the resistance increases the current decreases, if we take two points as an example, when the resistance is equal to 50 [ohms] the current is equal to 1[amp] and when the resistance is equal to 200 [ohms] the current tends to have a value below 0.5 [amp]. Thus demonstrating the decrease in current.

2)

Inverse proportionally, by definition we know that the law of ohm determines the voltage according to resistance and amperage. This is the voltage will be equal to the product of the voltage by the resistance.

V=I*R\\V = voltage [volts]\\I = current[amp]\\R = resistance [ohms]

where:

R =\frac{V}{I} \\or\\I=\frac{V}{R}

And whenever we have in a fractional number the denominator the variable we are interested in, we can say that this is inversely proportional to the value we are interested in determining. In this case, we can see from the two previous expressions that both the current and the resistance appear in the denominator, therefore they are inversely proportional to each other.

3)

If we place ourselves on the graph on the resistance axis, we see that at 50 [ohm] will correspond a current value equal to 1 [A].

4 0
3 years ago
Read 2 more answers
An object is 15 cm in front of a diverging lens with a
Rainbow [258]

A) See ray diagram in attachment (-6.0 cm)

By looking at the ray diagram, we see that the image is located approximately at a distance of 6-7 cm from the lens. This can be confirmed by using the lens equation:

\frac{1}{q}=\frac{1}{f}-\frac{1}{p}

where

q is the distance of the image from the lens

f = -10 cm is the focal length (negative for a diverging lens)

p = 15 cm is the distance of the object from the lens

Solving for q,

\frac{1}{q}=\frac{1}{-10 cm}-\frac{1}{15 cm}=-0.167 cm^{-1}

q=\frac{1}{-0.167 cm^{-1}}=-6.0 cm

B) The image is upright

As we see from the ray diagram, the image is upright. This is also confirmed by the magnification equation:

h_i = - h_o \frac{q}{p}

where h_i, h_o are the size of the image and of the object, respectively.

Since q < 0 and p > o, we have that h_i >0, which means that the image is upright.

C) The image is virtual

As we see from the ray diagram, the image is on the same side of the object with respect to the lens: so, it is virtual.

This is also confirmed by the sign of q in the lens equation: since q < 0, it means that the image is virtual

4 0
3 years ago
There are 3.3V passing through an orange power supply cable, and there are 0.025 ohms of resistance in the orange wire. How much
PIT_PIT [208]
P = V^2 / R.

So, 3.3^2 / 0.025 = 435.6W.

Note, you can get the power equation from:
P = V*I. Also, I = V/R.
Substituting V/R in for I in the 1st equation, you get P = V^2 / R.
5 0
3 years ago
An element has 4 protons, 5 neutrons, and 4 electrons. What is the atomic mass of the element? 4 5 8 9
alex41 [277]

at mass = protons+neutrons=9

5 0
3 years ago
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The forces acting on a sailboat are 390. N south and 180. N east. If the boat (including
velikii [3]

Answer:

180^2 + 390^2 = force ^2 (Pythagoras) root of force^2 = 429.5N approx resultant force Acceleration = Force/Mass 429.5/270 = 1.5907 ms^-2 in a Southwesterly direction.

Explanation:

4 0
2 years ago
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