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evablogger [386]

3 years ago

15

When you take your 1900-kg car out for a spin, you go around a corner of radius 53m with a speed of 13m/s. The coefficient of st

atic friction between the car and the road is 0.88. Assuming your car doesnt skid, what is the force exerted on it by static friction?

1 answer:

anastassius [24]3 years ago

3 0

Answer:

Ff = 6058.5N

Explanation:

The sum of forces is:

$Ff = m*a_c$

$Ff = m*V^2/R$

$Ff = 1900*13^2/53$

$Ff = 6058.5N$

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A change of temperature of 20 C is equivalent to a change in thermodynamic temperature of

Leto [7]

Answer:

20 K

Explanation:

It is given that,

The change in temperature is 20 C.

We need to find the change in thermodynamic temperature.

If teperauture T₁ = 0° C = 0+273 = 273 K

T₂ = 20° C = 20 + 273 = 293 K

The change in temperature,

$\Delta T=T_2-T_1\\\\=293-273\\\\=20\ K$

So, the change in temperature of 20°C is equivalent to 20 K.

7 0

3 years ago

Three guns are aimed at the center of a circle, and each fires a bullet simultaneously. The directions in which they fire are 12

ikadub [295]

Answer:

The unknown mass of the bullet is $m1=3.751x10^{-3} kg$

Explanation:

According to Newton's laws of motion, when a net external force acts on a body of mass <u><em>m</em></u> , it results in change in momentum of the body and is given by:

$F=\frac{P}{dt}$

Where:

P

is the linear momentum of the body

As a consequence, when there are no external forces acting on the body the total momentum remains conserved i.e.

Given:

$m_{2}=5.79x10^{-3}kg \\m_{3}=5.79x10^{-3}kg\\v_{2}=v_{3}=392 \frac{m}{s}\\$

For momentum along the y-direction to be zero, it is achieved when the equal masses are moving at angles of

θ1=180°, θ2=60°, θ3=-60°

Therefore, from conservation of momentum along x - direction:

$m_{1}*v_{1}*cos(180)+m_{2}*v_{2}*cos(60)+m_{3}*v_{3}*cos(-60)=0\\$ $m_{1}*605\frac{m}{s}*cos(180)+5.79x10^{-3}kg *392\frac{m}{s}*cos(60)+5.79x10^{-3}kg*392\frac{m}{s}*cos(-60)=0\\$

$-m_{1}*605+5.79x10^{-3}kg*196\frac{m}{s}+5.79x10^{-3}kg*196\frac{m}{s}=0\\m_{1}*605kg= 2.26968\frac{kg*m}{s}\\m_{1}=3.75 x10^{-3} kg$

3 0

3 years ago

A rocket is launched upward with a constant acceleration of 165 m/s^2. After 8.00 seconds of ascension a passenger on the rocket

Novay_Z [31]

To solve this problem we will apply the concepts related to the linear kinematic movement. We will start by finding the speed of the body from time and the acceleration given.

Through the position equations we will calculate the distance traveled.

Finally, using this same position relationship and considering the previously found speed, we can determine the time to reach your goal.

For time (t) and acceleration (a) we have to,

$t = 8s, a = 165m/s^2$

The velocity would be,

$u = a*t \\u = 165*8\\u = 1320m/s$

Now the position is,

$h= \frac{1}{2} at^2$

$h = \frac{1}{2} 165*8^2$

$h = 5280m$

Now with the initial speed and position found we will have the time is,

$h=ut +\frac{1}{2} at^2$

$-5280=1320t - \frac{1}{2} 9.8t^2$

$4.9t^2-1320t-5280=0$

Solving the polynomian we have,

$t = 273.33s = 4.56minutes$

Therefore the rocket will take to hit the ground around to 4.56min

5 0

3 years ago

The density of a solid material depends on two things .Name those two things

Amiraneli [1.4K]

Mass of an individual atoms or molecules

5 0

3 years ago

Read 2 more answers

Suppose a soup can is made from a sheet of steel19 which is .13 mm thick. If the can is 11 cm high and 6 cm in diameter, use dif

Flura [38]

Answer:

The can mass is 0,00359 kg or 3,59 g

Explanation:

1. Relevant Data:

Steel thickness= 0.13 mm or 0.013 mm

h=11 cm

d=6 cm

ρ=800 kg/m^3

2. Calculate mass from densisty equation:

$\rho=\frac{m}{v}$ , then $m=\rho .v$

We need to estimate the volume of the can to calculate the mass.

3. Estimate volume using differentials:

Cylinder volume equation is:

$V=\frac{1}{4}\pi d^{2}h$

Considering that the can is an object with a hole inside, then we need to estimate the real volume of the sheet of steel.

Using differentials we have:

$dV=\frac{1}{2}\pi Dh (dD)$

Then, we could say that $dD=0.013 cm$

Replacing the values of d, h and dD, we obtain:

$dV=\frac{1}{6}\pi (6 cm)(11 cm)(0,013 cm)$

$dV=0,4492 cm^3$

4. Calculate the mass

Convert volume unit into $m^3$

$0,4492 cm^3x\frac{1 m^3}{1x10^6 cm^3} =0,4492 x 10^-6 m^3$

Calculate mass

$m=\rho .v$

$m=8000 \frac{kg}{m^3}.0,4492 x10^-6 m^3$

$m=0,00359 kg =3,59 g$

5 0

4 years ago