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evablogger [386]

3 years ago

15

When you take your 1900-kg car out for a spin, you go around a corner of radius 53m with a speed of 13m/s. The coefficient of st

atic friction between the car and the road is 0.88. Assuming your car doesnt skid, what is the force exerted on it by static friction?

1 answer:

anastassius [24]3 years ago

3 0

Answer:

Ff = 6058.5N

Explanation:

The sum of forces is:

$Ff = m*a_c$

$Ff = m*V^2/R$

$Ff = 1900*13^2/53$

$Ff = 6058.5N$

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Answer:

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Explanation:

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$\beta=5.3 rad$

$I=I_0cos^2(\frac{\phi}{2})(\frac{sin\frac{\beta}{2}}{\frac{\beta}{2}})^2$

$I=5\times 10^{-4}cos^2(\frac{7.74}{2})(\frac{sin\frac{5.3}{2}}{\frac{5.3}{2}})^2$

$I=8.8\times 10^{-6} W/m^2$

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To know more about balls visit:-

brainly.com/question/19930452

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