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Flauer [41]
2 years ago
9

Your’re working with a patient who suddenly falls. You should

Physics
2 answers:
Doss [256]2 years ago
8 0

don't feel bad for him just move on.

Alenkinab [10]2 years ago
7 0

Answer:

sss

Explanation:

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Newton's Principle states that the buoyant force on an object is equal to weight of the fluid displaced by the object.
Ilia_Sergeevich [38]

Answer:

False it wasn't Newton who theorised it, it was Archimedes

Explanation:

3 0
2 years ago
How much mass dose a vehicle have if it needs 29000 Newton’s of force to accelerate it at a rate of 4m/s
Olin [163]
F=ma
m=F/a
m=29000/4
m= 7250kg
4 0
2 years ago
A 1200-kg car is travelling east at a rate of 9 m/s. A 1600-kg truck is travelling south at a rate of 13 m/s. The truck accident
weeeeeb [17]

Answer:

Around 3.57m/s

Explanation:

p=mv

Let's denote the momentum, mass, and velocity of the car with the subscript 1, and for the truck use 2. After the collision, the combined momentum can be denoted with the subscript 3.

p_1=1200\cdot 9=10800 \\\\p_2=1600\cdot 13=20800 \\\\20800-10800=10000 \\\\1200kg+1600kg=2800kg \\\\10000=2800v_3 \\\\v_3\approx 3.57m/s

Hope this helps!

3 0
3 years ago
A space explorer is moving through space far from any planet or star. He notices a large rock, taken as a specimen from an alien
yaroslaw [1]
He should push it gently.
This is because the forces of resistance this situation are minimal, so the rock will not slow as it would on Earth. Kicking the rock may result in it travelling too fast and hitting something else, causing damage. Moreover, the rock could start rebounding off of surfaces and create havoc. 
3 0
3 years ago
A trumpet player is tuning his instrument by playing an A note simultaneously with the first-chair trumpeter, who has perfect pi
KIM [24]

To develop this problem, it is necessary to apply the concepts related to Beat

The Beat is an acoustic phenomenon that is generated by two sine waves interfering with slightly different frequencies. The beat frequency is equal to the difference in the frequencies of the two original waves:

f_{bat} = |(f_1 \pm f_B)|

Our values are given as

f_1 = 440Hz

f_B = 2.1Hz

For the particular case we have two possible frequencies:

1) f_{bat} = |(f_1 - f_B)|

f_{bat} = |(440 - 2.1)|

f_{bat} = 437.9Hz

2) f_{bat} = |(f_B + f_1)|

f_{bat} = |(440 +2.1)|

f_{bat} = 442.1Hz

Therefore the two possibles frequencies of the other players note are 437.9Hz and 442.1Hz

4 0
3 years ago
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