A rock is dropped from a 200 m high cliff. How long does it take to fall (a) the first 100 m and (b) the last 50 m?
The basic equation you want is:
s=at22
Solving for t:
t=2sa−−−√
We’ll assume a=9.8 , so 2a−−√=14.9−−−√≈0.4518
So, for (a)s=100 , so t=0.4518100−−−√=4.518
The total time is 0.4518200−−−√≈6.389
The time to fall 150 m is 0.4518150−−−√≈5.533
So the time to fall the last 50 m is 6.389 - 5.533 = 0.856 seconds
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The coefficient is needed in front of NaNO3 to balance the equation is 2.
<h3>What is balanced equation?</h3>
When in a chemical reaction, both the product elements or compounds should have number of moles equal to that of the elements or compounds of reactants.
In the given chemical reaction equation,
Na2S + Zn(NO3)2 → ZnS + _NaNO3
Number of moles of S is 1 on both the product and reactant side. Zn has 1 mole on both side. NO3 has 2 mole and Na has 2 mole on reactant side. So to balance the equation, Na and NO3 both must have 2 moles on product side.
Thus, the coefficient is needed in front of NaNO3 to balance the equation is 2.
Learn more about balanced equation.
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Answer:
Explanation:
We shall find first the velocity of ball at the time when string breaks. Let it be v . During its fall on the ground , 1.02 m below, we use the formula
h = 1/2 gt² where t is time of fall .
1.02 = 1/2 x 9.8 x t²
t²= .2081
t = .456
During this time it travels horizontally at distance of 2.5 m with uniform velocity of v
v x .456 = 2.5
v = 5.48 m /s
centripetal acceleration
= v² / r where r is radius of the circular path
= 5.48² / .478
= 62.82 m /s²
0.09 / 6.37 x 10⁶ = 1.4129 x 10⁻⁸
The radius of the baseball is 1.4129 x 10⁻⁸ the radius of the Earth.
Answer:
yes
Explanation:
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