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Flauer [41]
3 years ago
9

Your’re working with a patient who suddenly falls. You should

Physics
2 answers:
Doss [256]3 years ago
8 0

don't feel bad for him just move on.

Alenkinab [10]3 years ago
7 0

Answer:

sss

Explanation:

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A uniform electric field of magnitude 7.0 ✕ 104 N/C passes through the plane of a square sheet with sides 5.0 m long. Calculate
Vadim26 [7]

Answer:

1.52*10^6 Nm^2/C

Explanation:

Given that:

Electrical field E = 7.0 * 10^{-4}N/C

square side l = 5.0 m

Area A = 5.0 * 5.0

= 25.0 m²

Angle ( θ ) between area vector and E = (90° - 60°)

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The flux \phi_E can now be determined by using the expression

\phi_E = E*A*Cos \theta

\phi_E = 7.0 * 10^{-4}N/C *25.0m*Cos 30^0

\phi_E = 1515544.457 Nm^2/C

\phi_E = 1.52*10^6 Nm^2/C

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3 years ago
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75 POINTS AND BRAINLY
kramer

Answer:

B=work=power/time

Explanation:

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A vertical straight wire 35.0 cmcm in length carries a current. You do not know either the magnitude of the current or whether t
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Answer:

1.714\ \text{A}

Explanation:

F = Magnetic force = 0.018 N

B = Magnetic field = 0.03 T

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Magnetic force is given by

F=IBL\sin\theta\\\Rightarrow I=\dfrac{F}{BL\sin\theta}\\\Rightarrow I=\dfrac{0.018}{0.03\times 35\times 10^{-2}\times \sin90^{\circ}}\\\Rightarrow I=1.714\ \text{A}

The magnitude of the current is 1.714\ \text{A}.

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3 years ago
A. Test used to measure flexibility B. The elasticity of muscle groups C. Test approve by the president of the United States D.
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3 years ago
After landing on an unfamiliar planet, a space explorer constructs a simple pendulum of length 54.0 . The expl? After landing on
iogann1982 [59]
<span>We can find the period P of one cycle, and then we can use the period to find the gravitational acceleration g on this planet. P = (132 s) / (107 cycles) = 1.2336 s/cycle The period P is 1.2336 seconds. This means that it takes 1.2336 seconds for the pendulum to swing back and forth one. Now we can use the period P to find the gravitational acceleration g. The equation for the period of a pendulum is as follows: P = 2 pi \sqrt{L/g} P^2 = (4 pi^2) L / g g = (4 pi^2) L / P^2 g = (4)(pi^2)(0.540 m) / (1.2336 s)^2 g = 14.0 m/s^2 The acceleration of gravity on the planet is 14.0 m/s^2.</span>
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