Question

the system shown above is released from rest. if friction is negligible, the acceleration of the 4.0 kg block sliding on the table shown above is most nearly

Answer 1

The acceleration of the first block (4 kg) is -9.8 m/s².

The given parameters:

• Mass of the first block, m₁ = 4.0 kg
• Mass of the second block, m₂ = 2.0 kg

The net force on the system of the two blocks is calculated as follows;

$m_2 g - T = m_1 a$

where;

• T is the tension in the connecting string due weight of the first block

$m_2 g - m_1 g = m_1 a\\\\a = \frac{m_2 g - m_1g}{m_1} \\\\a = \frac{g(m_2 - m_1)}{m_1} \\\\a = \frac{9.8(2-4)}{2} \\\\a = -9.8 \ m/s^2$

Thus, the acceleration of the first block (4 kg) is -9.8 m/s².

Learn more about net force on two connected blocks here: brainly.com/question/13539944