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Gre4nikov [31]
3 years ago
5

How do the electrons in bonds (bonding domains) differ from lone pairs (non-bonding domains)?

Chemistry
1 answer:
max2010maxim [7]3 years ago
5 0

The electrons in bonds (bonding domains) differ from lone pairs (non-bonding domains) is because the bonding domains are bonded to the central atom vs the lone pairs are just stuck on as extra electrons. The difference of bonding domains from non-bonding domains is that the bonding domains are bonded to the central atom and the non-bonding domains are just stuck on as extra electrons.

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In the chemical formula 2so2, how many total atoms of sulfur (s) are there? 1 2 4
babunello [35]
Sulfur has the coefficient of 2, and nothing else. This indicates Sulfur has 2 atoms. 


<span>Oxygen on the other hand, has a subscript of 2, as well as the coefficient of 2. Multiplying those, and you see Oxygen has 4 atoms. 
</span>
So your answer is 2

Also remember there is a 2 in front of S meaning there are 2 Sulfurs. 
<span>If it was S02 it would be 1 Sulfur as there is no number in front of sulfer. </span>

<span>Remember the number in front of a element, represents how many atoms there are :)</span>
6 0
3 years ago
What part of the atom is responsible for the behavior of the alpha particles?
ivann1987 [24]

Answer:

nucleus

Alpha particles are subatomic fragments consisting of two neutrons and two protons. Alpha radiation occurs when the nucleus of an atom becomes unstable (the ratio of neutrons to protons is too low) and alpha particles are emitted to restore balance.

Explanation:

8 0
3 years ago
For a gaseous reaction, standard conditions are 298 K and a partial pressure of 1 atm for all species. For the reaction 2 NO ( g
enyata [817]

Answer:

ΔG = -61.5 kJ/mol (<u>Spontaneous process</u>)

Explanation:

2 NO (g)  +  O₂  (g)   ⇄  2NO₂ (g)

Let's apply the thermodynamic formula to calculate the ΔG

ΔG = ΔG° + R .T . lnQ

We don't know if the gases are at equilibrium, that's why we apply Q (reaction quotient)

ΔG = - 69 kJ/mol + 8.31x10⁻³ kJ/K.mol . 298K . ln Q

How can we know Q? By the partial pressures (Qp)

P NO = 0.450atm

PO₂ = 0.1 atm

PNO₂ = 0.650 atm

Qp = [NO₂]² / [NO]² . [O₂]

Qp = 0.650² / 0.450² . 0.1 = 20.86

ΔG = - 69 kJ/mol + 8.31x10⁻³ kJ/K.mol . 298K . ln 20.86

ΔG = -61.5 kJ/mol (<u>Spontaneous process</u>)

5 0
3 years ago
1) 8700cm = ______ km
mart [117]

1. 0.087

2. 0.534

3. 1210000

4. 540

5. 0.00234

8 0
3 years ago
Which of the following is not a characteristic of a metal?
jolli1 [7]

Answer:

B. Poor conductor.

Explanation:

It cannot be A, as only 1 metal is not solid at room temp.

It cannot be C, as most metals are ductile.

It cannot be D, as most metals are malleable.

This leaves B, which is not true about metals, as a lot are very good conductors.

3 0
2 years ago
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