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Vinil7 [7]
1 year ago
15

What would be the mass in grams of 8.94 x 10 22 formula units of copper(II) fluoride, CuF 2

Chemistry
1 answer:
Nadya [2.5K]1 year ago
5 0

The mass in grams of 8.94×10²² formula units of CuF₂ is 15.07 g

<h3>Avogadro's hypothesis </h3>

6.02×10²³ formula units = 1 mole of CuF₂

But

1 mole of CuF₂ = 101.5 g

Thus,

6.02×10²³ formula units = 101.5 g of CuF₂

<h3>How to determine the mass of 8.94×10²² formula units of CuF₂</h3>

6.02×10²³ formula units = 101.5 g of CuF₂

Therefore,

8.94×10²² formula units = (8.94×10²² × 101.5 ) / 6.02×10²³

8.94×10²² formula units = 15.07 g of CuF₂

Thus, 8.94×10²² formula units are present in 15.07 g of CuF₂

Learn more about Avogadro's number:

brainly.com/question/26141731

#SPJ1

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Dimitri Ivanovich Mendeleev

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Brian is making a cake for his friend's birthday. He combines the ingredients for the cake and then pours the batter into two pa
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3 years ago
In which set of elements would all members be expected to have very similar chemical properties?A) O, S, SeB) S, Se, SiC) N, O,
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Answer:

A. O, S, Se

Explanation:

If you look up Oxygen (O), Sulfur (S) and Selenium (Se) in the periodic table, you will see that these three fall under the same column. In the periodic table, elements are arranged in rows and columns. Columns are called groups. The elements that fall under the same group share similar chemical properties.

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6 0
3 years ago
A scientist measures the standard enthalpy change for the following reaction to be -327.2 kJ : P4O10(s) 6 H2O(l)4H3PO4(aq) Based
OleMash [197]

Answer:

ΔH°f P4O10(s) = - 3115.795 KJ/mol

Explanation:

  • P4O10(s) + 6H2O(l) ↔ 4H3PO4(aq)
  • ΔH°rxn = ∑νiΔH°fi

∴ ΔH°rxn = - 327.2 KJ

∴ ΔH°f H2O(l) = - 285.84 KJ/mol

∴ ΔH°F H3PO4(aq) = - 1289.5088 KJ/mol

⇒ ΔH°rxn = (4)(- 1289.5088) - (6)(- 285.84) - ΔH°f P4O10(s) = - 327.2 KJ

⇒ ΔH°f P4O10(s) = - 5158.035 + 1715.04 + 327.2

⇒ ΔH°f P4O10(s) = - 3115.795 KJ/mol

5 0
3 years ago
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