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2 years ago

What would be the mass in grams of 8.94 x 10 22 formula units of copper(II) fluoride, CuF 2

Chemistry

1 answer:

Nadya [2.5K]2 years ago

5 0

The mass in grams of 8.94×10²² formula units of CuF₂ is 15.07 g

<h3>Avogadro's hypothesis </h3>

6.02×10²³ formula units = 1 mole of CuF₂

But

1 mole of CuF₂ = 101.5 g

Thus,

6.02×10²³ formula units = 101.5 g of CuF₂

<h3>How to determine the mass of 8.94×10²² formula units of CuF₂</h3>

6.02×10²³ formula units = 101.5 g of CuF₂

Therefore,

8.94×10²² formula units = (8.94×10²² × 101.5 ) / 6.02×10²³

8.94×10²² formula units = 15.07 g of CuF₂

Thus, 8.94×10²² formula units are present in 15.07 g of CuF₂

Learn more about Avogadro's number:

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In the process of attempting to characterize a substance, a chemist makes the following observations: (a) The substance is a sil

Amiraneli [1.4K]

The question is incomplete, this is the complete question;

In the process of attempting to characterize a substance, a chemist makes the following observations. Which are physical properties and which are chemical properties?

(a) The substance is a silvery white, lustrous metal.

(b) The substance melts at 649 ∘C

(d) The density of the substance at 20 ∘C is 1.738 g/cm³.

(e) The substance burns in air, producing an intense white light.

(f) The substance reacts with chlorine to give a brittle white solid.

(g) The substance can be pounded into thin sheets or drawn into wires.

(h) The substance is a good conductor of electricity.

Answer:

(a) Physical

(b) Physical

(d) Physical

(e) Chemical

(f) Chemical

(g) Physical

(h) Physical

Explanation:

(a) The substance is a silvery white, lustrous metal - is appearance which is physical.

(b) The substance melts at 649 ∘C metling point is a physical measurement

(d) The density of the substance at 20 ∘C is 1.738 g/cm3 how heavy a substance is,is physical.

(e) The substance burns in air, producing an intense white light. Burning is a chemical change. It is a reaction of a substance with oxygen

(f) The substance reacts with chlorine to give a brittle white solid. This is a chemical reaction as the question says.

(g) The substance can be pounded into thin sheets or drawn into wires. Ductility is a physical change, the substance remains chemically unchanged

(h) The substance is a good conductor of electricity. Any conductivity is physical, the substance remains chemically unchanged

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3 years ago

Nitration of 1,4−dimethylbenzene (p−xylene) gives a single product having the molecular formula c8h9no2 in high yield. draw this

GarryVolchara [31]

Structure is in document below.
The mononitration of p-xylene can be easily carried out at 30 degrees C.
Para-xylene<span> (</span><span>p-xylene</span><span>) is an </span>aromatic hydrocarbon, <span>one of the three </span>isomers<span> of </span>dimethylbenzene. Para-xylene is colorless and highly flammable, not acutely toxic and has some <span>narcotic effects.</span>

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8 0

3 years ago

PLEASE HELP WILL REWARD BRAINLIEST

riadik2000 [5.3K]

The answer is the principal quantum number

Hope this helps

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3 years ago

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Please Help! I just started balancing equations and my teacher gave me this. Thanks in advance! :D

Alenkasestr [34]

So you need to put numbers before each compound to make sure there are the exact same number of elements on each side. If you put a 4 before NH4 there are 4 Nitrogen and now 16 hydrogen. I just played around with numbers and guessed until I got them even.

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3 years ago

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A compound with molecular formula C5H10O2 has the following 1H NMR spectrum: 1.15 (t, 3H), 1.25 (t, 3H), 2.33 (q, 2H), 4.13 (q,

Vilka [71]

Answer:

Ethyl propionate

Explanation:

Calculating the double bond equivalence as:

DBE = C - (H/2) - (X/2) + (N/2) +1

Where

C is the number of carbon atoms

N is the number of nitrogen atoms

X is the number of halogens

H is the number of hydrogen atoms

So, according to the formula, $C_5H_{10}O_2$

DBE = 5 - (10/2) - (0/2) + (0/2) +1 = 1

It means there is one double bond or one ring.

from the NMR signal, it is clear that compound has two triplet and two quardrate group that means two -CH3 and two -CH2 groups are present.

From the splitting information, it is clear that each the -CH2- group is next to a -CH3, and vice-versa. In this case ring structure is not possible.

The chemical shift of two protons 4.13 ppm(q, 2H) is for protons next to an O atom, therefore, compound must have

$-OCH_2CH_3$ .

Then the signal at 2.33 is for a -CH2-group next to a C=O. So compound must have a structure CH3-CH2-C=O. Now, there is only one way to complete the structure - by bonding the O to the C=O carbon.

So the compound is ethyl propionate

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3 years ago