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3 years ago

When traveling from air to a solid, what would you expect a sound wave to do?

Physics

2 answers:

sdas [7]3 years ago

8 0

A. Speed up is the answer. Hope it is right.

ANTONII [103]3 years ago

3 0

Answer: The correct option is A.

Explanation:

Sound is a longitudinal wave. In longitudinal wave, the particles vibrate parallel to the direction of the propagation of the wave.

Sound wave consists of compression and rarefaction.

It needs medium to travel. It can travel in solid, liquid and gas. Denser the medium, more will be the speed of the sound.

Sound wave travels faster in solid in comparison to liquid.

In the given problem, when traveling from air to a solid then the speed of the sound wave will speed up.

Therefore, the correct answer is A.

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What mechanical layer lies below the lithosphere

joja [24]

The <span>asthenosphere is under the lithosphere.</span>

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3 years ago

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A 3-kg mass is in free fall. What is the velocity of the mass after 7 seconds??

dmitriy555 [2]

69 ms. I hope that helps

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3 years ago

a person can throw a 300 gram ball at 25 m/s the maximum height the person can throw the ball on Earth?

jolli1 [7]

Answer:

Elevation =31.85[m]

Explanation:

We can solve this problem by using the principle of energy conservation. This consists of transforming kinetic energy into potential energy or vice versa. For this specific case is the transformation of kinetic energy to potential energy.

We need to first identify all the input data, and establish a condition or a point where the potential energy is zero.

The point where the ball is thrown shall be taken as a reference point of potential energy.

$E_{p} = E_{k} \\where:\\E_{p}= potential energy [J]\\ E_{k}= kinetic energy [J]$

m = mass of the ball = 300 [gr] = 0.3 [kg]

v = initial velocity = 25 [m/s]

$E_{k}=\frac{1}{2} * m* v^{2} \\E_{k}= \frac{1}{2} * 0.3* (25)^{2} \\E_{k}= 93.75 [J]$

$93.75=m*g*h\\where:\\g = gravity = 9.81 [m/s^2]\\h = elevation [m]\\replacing\\h=\frac{E_{k}}{m*g} \\h=\frac{93.75}{.3*9.81} \\h=31.85[m]$

5 0

4 years ago

The current theory of the structure of the

IRISSAK [1]

1) The mass of the continent is $3.3\cdot 10^{21} kg$

2) The kinetic energy of the continent is 624 J

3) The speed of the jogger must be 4 m/s

Explanation:

We start by finding the volume of the continent. We have:

$L = 5850 km = 5.85\cdot 10^6 m$ is the side

$t = 35 km = 3.5\cdot 10^4 m$ is the depth

So the volume is

$V=L^2 t = (5.85\cdot 10^6)^2 (3.5\cdot 10^4)=1.20\cdot 10^{18} m^3$

We also know that its density is

$d=2750 kg/m^3$

Therefore, we can find the mass by multiplying volume by density:

$m=dV=(2750)(1.20\cdot 10^{18})=3.3\cdot 10^{21} kg$

The kinetic energy of the continent is given by:

$K=\frac{1}{2}mv^2$

where

$m=3.3\cdot 10^{21} kg$ is its mass

v = 3.2 cm/year is the speed

We have to convert the speed into m/s. We have:

3.2 cm = 0.032 m

$1 year = 1(365)(24)(60)(60)=3.15\cdot 10^7 s$

So, the speed is:

$v=\frac{0.032 m}{3.15 \cdot 10^7 s}=1.02\cdot 10^{-9} m/s$

So, we can now find the kinetic energy:

$K=\frac{1}{2}(1.20\cdot 10^{21})(1.02\cdot 10^{-9})^2=624 J$

Here we have a jogger of mass

m = 78 kg

And the jogger has the same kinetic energy of the continent, so

K = 624 J

The kinetic energy of the jogger is given by

$K=\frac{1}{2}mv^2$

where v is the speed of the jogger.

Solving for v, we find the speed that the jogger must have:

$v=\sqrt{\frac{2K}{m}}=\sqrt{\frac{2(624)}{78}}=4 m/s$

Learn more about kinetic energy:

brainly.com/question/6536722

#LearnwithBrainly

3 0

3 years ago

An incandescent bulb is supplied with

Serga [27]

Answer:

Efficiency = 5%

Explanation:

Given that,

Supplies energy to the bulb = 100 J

Transferred energy by the bulb = 5 J

We need to find the efficiency of the bulb. It can be given by "

$\eta=\dfrac{\text{useful energy out}}{\text{useful energy in}}\times 100\\\\=\dfrac{5}{100}\times 100\\\\=5\%$

So, the efficiency of the bulb is 5%.

8 0

3 years ago