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Mandarinka [93]
3 years ago
11

When traveling from air to a solid, what would you expect a sound wave to do?

Physics
2 answers:
sdas [7]3 years ago
8 0
A. Speed up is the answer. Hope it is right.

ANTONII [103]3 years ago
3 0

Answer: The correct option is A.

Explanation:

Sound is a longitudinal wave. In longitudinal wave, the particles vibrate parallel to the direction of the propagation of the wave.

Sound wave consists of compression and rarefaction.

It needs medium to travel. It can travel in solid, liquid and gas.  Denser the medium, more will be the speed of the sound.

Sound wave travels faster in solid in comparison to liquid.

In the given problem, when traveling from air to a solid then the speed of the sound wave will speed up.

Therefore, the correct answer is A.

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A uniform magnetic field passes through a horizontal circular wire loop at an angle 19.5 ∘ from the vertical. The magnitude of t
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To solve this problem, we will apply the concepts related to Faraday's law that describes the behavior of the emf induced in the loop. Remember that this can be expressed as the product between the number of loops and the variation of the magnetic flux per unit of time. At the same time the magnetic flux through a loop of cross sectional area is,

\Phi = BA Cos \theta

Here,

\theta = Angle between areal vector and magnetic field direction.

According to Faraday's law, induced emf in the loop is,

\epsilon= -N \frac{d\Phi }{dt}

\epsilon = -N \frac{(BAcos\theta)}{dt}

\epsilon = -NAcos\theta \frac{dB}{dt}

\epsilon = -N\pi r^2 cos\theta \frac{d}{dt} ( ( 3.75 T ) + ( 3.05T/s ) t + ( -6.95 T/s^2 ) t^2)

\epsilon = -N\pi r^2 cos\theta( (3.05T/s)-(13.9T/s)t )

At time t = 5.71s,  Induced emf is,

\epsilon = -(1) \pi (0.220m)^2 cos(19.5\°)(  (3.05T/s)-(13.9T/s)(5.71s))

\epsilon = 10.9V

Therefore the magnitude of the induced emf is 10.9V

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